Validating Stokes' Theorem Formula for Triangular Surface on y-z Plane?

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Homework Help Overview

The discussion revolves around validating Stokes' Theorem for a specific function using a triangular surface on the y-z plane defined by the corners at the origin, (0,2,0), and (0,0,2).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to compute the curl of a vector field and integrate it over the triangular surface but is uncertain about the integration bounds and the implications of setting x=0. There is also a question regarding how to validate both sides of Stokes' Theorem.

Discussion Status

Participants are actively discussing the setup of the problem and the integration process. Some have pointed out missing information, such as the specific function involved, which may hinder progress. There is no explicit consensus on the approach yet, but guidance is being sought regarding the integration steps.

Contextual Notes

There is a noted lack of clarity regarding the function to be used in Stokes' Theorem, which is essential for the discussion. Additionally, the original poster expresses confusion about the integration process and the bounds involved.

JB91
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Homework Statement


Show that both sides of the Stoke's Theorem formula are valid for the function F= using the triangular surface on the y-z plane with corners at the origin, (0,2,0) and (0,0,2).

Homework Equations


Stokes Theorem equation( not sure how to write it out here) [/B]

The Attempt at a Solution


Took the curl of V, ended up with <-2y,-3z,-x> but when I go to integrate do I set x=0 and then dx=0 as well? So then, with y=2-z , bounds on the integrals are 0-2 and 0-(2-z) so (INT)(INT)(-3z)dydx with the bounds? But when I do this I end up with -4 ... Not sure where I am going wrong and I don't know how to prove the other side of the equation. Any help would be greatly appreciated.
 
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JB91 said:
1. The problem statement, all
and given/known data

Show that both sides of the Stoke's Theorem formula are valid for the function F=
You left out the function so we can't answer your question!
using the triangular surface on the y-z plane with corners at the origin, (0,2,0) and (0,0,2).

Homework Equations


Stokes Theorem equation( not sure how to write it out here) [/B]

The Attempt at a Solution


Took the curl of V, ended up with <-2y,-3z,-x> but when I go to integrate do I set x=0 and then dx=0 as well? So then, with y=2-z , bounds on the integrals are 0-2 and 0-(2-z) so (INT)(INT)(-3z)dydx with the bounds? But when I do this I end up with -4 ... Not sure where I am going wrong and I don't know how to prove the other side of the equation. Any help would be greatly appreciated.
 
Duplicate thread to https://www.physicsforums.com/threads/stokes-theorem.806286
 
Last edited by a moderator:
The name is "Stokes", not "Stoke". So it should be "Stokes' theorem".
 

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