Values for which a set of vectors form a basis of Rn

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SUMMARY

The discussion centers on determining the values of λ for which the set of vectors {(λ^2-5, 1, 0), (2, -2, 3), (2, -3, -3)} forms a basis of ℝ^3. It is established that the vectors must be linearly independent and span ℝ^3. The row reduction of the corresponding matrix indicates that the identity matrix is achieved only when λ^2 - 5 = 0, leading to the conclusion that λ must equal ±√5 for the vectors to form a basis.

PREREQUISITES
  • Understanding of linear independence in vector spaces
  • Knowledge of row reduction techniques for matrices
  • Familiarity with the concept of spanning sets in ℝ^3
  • Basic algebraic manipulation involving quadratic equations
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  • Study linear independence and spanning sets in vector spaces
  • Learn about row reduction methods and echelon forms
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Students studying linear algebra, educators teaching vector spaces, and anyone interested in the properties of bases in ℝ^3.

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Homework Statement



For what value(s) of λ is the set of vectors {(λ^2-5, 1, 0), (2, -2, 3), (2, -3, -3)} form a basis of ℝ^3

Homework Equations



in order for a vector to form a basis it has to span R3 and the set has to be linearly independent.

The Attempt at a Solution


i tried doing row reduction on the matrix but i end up with identity matrix.
which means it would be a basis for any value, which is impossible.

the matrix I'm getting is [1, 0, 0 ; 0, 1, 0; λ^2 -5, 0, 4,]anybody??
 
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What do you mean you get the identity matrix when you then write "the matrix I'm getting is [1, 0, 0 ; 0, 1, 0; λ^2 -5, 0, 4,]"? That's not row reduced. Or, rather, it is row reduced if and only if λ^2 -5= 0.
 

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