For a vertical circular motion, its standard to solve for tension at the 4 common points on the circle (North, South, East, West) My question is, is it possible to solve for tension at other locations? Example :https://www.dropbox.com/s/c4q1sprphol2tzb/20151127_020345.jpg?dl=0 Can i resolve vertically and horizontally, I.e. vertically : Tcosθ =mg, Horizontally : Tsinθ=[mv^2/r]sinθ Doesn't seem quite right though.. Can advise/explain on how to approach/solve this questions? Thanks a million!!!