Vector Addition: Finding Resultant and Direction - Easy Homework Solution

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SUMMARY

The discussion centers on calculating the resultant of three vectors with specific magnitudes and angles. The vectors are defined as Vector 1 = 18 at 40 degrees, Vector 2 = 10 at 72 degrees, and Vector 3 = 22 at 55 degrees. The calculated magnitude of the resultant is 3.64, while the direction is approximately -58.5 degrees. However, it is crucial to clarify that the resultant is a vector with both magnitude and direction, and the angle should specify the quadrant for accurate interpretation.

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  • Familiarity with trigonometric functions: sine and cosine
  • Knowledge of arctangent and its limitations in angle determination
  • Basic concepts of vector addition and resultant vectors
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Homework Statement



I have three vectors and I need to find the resultant of the three vectors and direction.

Homework Equations



*All angles are with the horizontal

Vector 1 = 18 at an angle of 40 degrees (First Quadrant)
Vector 2 = 10 at an angle of 72 degrees (Second Quandrant)
Vector 3 = 22 at an angle of 55 degrees (Third Quadrant)

The Attempt at a Solution



In the X I got: 18cos(40) - 10cos(72) - 22cos(55) = -1.9
In the Y I got: 18sin(40) + 10 sin(72) - 22sin(55) = 3.1

√(-1.92 + 3.12) = 3.64 is the resultant

tan-1(3.1/-1.9) = -58.5 degrees is the direction/angle

I just need confirmation whether this is right or wrong. =)
 
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Looks good. Well, almost perfect. You should be a little careful with your terminology.

The resultant is a vector, the sum of the three vectors, and it has a magnitude and direction. The 3.64 you found is the magnitude of the resultant, not the resultant itself.

For the direction, you need to be a little careful because arctangent only returns angles between -90 degrees and +90 degrees. You should give a little more information to indicate exactly what the angle is, e.g. which quadrant, measured relative to what, etc.
 

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