What is the resultant of the vector from this impact?

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Homework Help Overview

The problem involves two individuals kicking a ball with specified forces at a given angle, leading to a question about the resultant vector from the impact. The context is rooted in vector addition and forces in physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various algebraic approaches to calculate the resultant vector, with some expressing difficulty in following the numerical logic presented. There are questions regarding the correct application of significant figures in the final answer.

Discussion Status

There is ongoing dialogue about the methods used to calculate the resultant vector, with some participants providing feedback on the clarity of the algebraic steps. Guidance on significant figures has been offered, indicating a productive exploration of the topic.

Contextual Notes

Participants are considering the implications of significant figures based on the precision of the input data, which adds complexity to the discussion. There is also a mention of potential errors in the calculations presented by the original poster.

j doe
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Homework Statement


two people kick a ball. one of them kicks it with a force of 215.0 Newtons. the other one with 189.0 Newtons. their approach creates a 210.0 degree angle at the point of impact and causes the ball to go in a different direction. what is the resultant of the vector from this impact?

Homework Equations

The Attempt at a Solution


215.0^2 = 46,225.0

189.0^2 = 35,721.0

46,225.0 + 35,721.0 = 81,946.0

2 x 189.0 = 378.0 + 215.0 = 81,270cos(30) = 70,381.88457

81,946.0 - 70,381.88457 = 11,564.11543

√11,564.11543 = 107.5365772 Newtons
 
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It's very hard to reverse engineer your logic from a string of numbers. Please write your steps algebraically.
 
haruspex said:
It's very hard to reverse engineer your logic from a string of numbers. Please write your steps algebraically.
  • magnitude^2=215^2+189^2-2*215*210*cos(30degrees)=61^2N
 
j doe said:
  • magnitude^2=215^2+189^2-2*215*210*cos(30degrees)=61^2N
That was easier to follow (though still not exactly algebraic) but now you seem to have plugged in a wrong number at one point and got a wrong answer.
I agree with your original 107, but you quote too many significant digits. Never quote more in the answer than the form of the input data implies.
 
haruspex said:
That was easier to follow (though still not exactly algebraic) but now you seem to have plugged in a wrong number at one point and got a wrong answer.
I agree with your original 107, but you quote too many significant digits. Never quote more in the answer than the form of the input data implies.
how many significant figures am i suppose to have and how can i tell?
 
j doe said:
how many significant figures am i suppose to have and how can i tell?
Each number you were given was quoted to four significant figures, so use the same in the answer. Usually, you should use the same as the least precise input number, but in reality it is more complicated than that.
If you care to, you can experiment with this. For each of the three numbers given, consider the highest and lowest exact number that is consistent with it. E.g. 210.0 degrees is anything from 209.95 to 210.05. That gives you eight combinations of extreme values, each combination giving a slightly different answer. What is the range of answers that results?
(But this is probably well beyond what you are expected to do here.)
 

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