Vector Addition Homework: Multiplying Vectors & Gaussian Elimination

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SUMMARY

The discussion centers on the application of Gaussian elimination in vector addition, specifically addressing the transformation of the vector (1, 1, 1) to (3, 3, 3) through scalar multiplication. Participants confirm that multiplying a vector by a scalar, such as 3, is permissible and serves to simplify arithmetic operations. The conversation clarifies that the expression (1, 1, 1) = (3/3, 3/3, 3/3) = (1/3)(3, 3, 3) effectively illustrates the manipulation of vectors under Gaussian elimination principles.

PREREQUISITES
  • Understanding of vector operations, including addition and scalar multiplication.
  • Familiarity with Gaussian elimination techniques in linear algebra.
  • Basic knowledge of mathematical notation and vector representation.
  • Ability to interpret and manipulate fractions in vector equations.
NEXT STEPS
  • Study the principles of Gaussian elimination in detail.
  • Explore scalar multiplication of vectors and its implications in linear transformations.
  • Learn about vector spaces and their properties in linear algebra.
  • Practice solving vector equations using various scalar values.
USEFUL FOR

Students studying linear algebra, educators teaching vector operations, and anyone seeking to enhance their understanding of Gaussian elimination and vector manipulation techniques.

g.lemaitre
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Homework Statement


Screenshot2012-07-14at25427AM.png

Homework Equations


The Attempt at a Solution


Do you see how 1 1 1 changes to 3 3 3. i know why gaussian elimination you can change any vector by multiplying it by anything you want. but for some reason i have difficulty believing that you're allowed to do that here. is that what they're doing? just multiplying that vector by 3 so as to facilitate the arithmetic. Or maybe they're multiplying both vectors by 3, so as to get rid of the 1/3, but that doesn't explain how the 1/3 gets on the left side of the parentheses.
 
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There is nothing wrong with

(1 1 1) = (\frac{3}{3} \frac{3}{3} \frac{3}{3}) =\frac{1}{3}(3 3 3)
 
ok, thanks
 

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