Vector Analysis: Show x,y in Vn can be Separated into y┴ & y//

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Homework Help Overview

The problem involves vector analysis in a vector space Vn, specifically focusing on decomposing a vector y into two components: one that is parallel to another vector x and one that is perpendicular to x. The original poster attempts to demonstrate this decomposition while adhering to certain mathematical constraints.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of decomposing vector y into components y┴ and y//, with some suggesting the use of vector projections. The original poster expresses uncertainty about how to proceed after establishing a relationship involving k, the scalar multiplier.

Discussion Status

There is ongoing exploration of different methods to achieve the vector decomposition. Some participants have suggested avoiding certain forms of vector projections, while others are considering alternative expressions for the components. The discussion reflects a variety of interpretations and approaches without reaching a consensus.

Contextual Notes

Participants are navigating constraints related to the definitions of vector components and the requirement to express y in terms of y┴ and y//. There is mention of avoiding trigonometric forms in the context of vector projections.

dpa
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Homework Statement



Let x,y is in Vn, such that x is not equal to zero.
Show that you can find vectors y and y// is in Vn such that y=y + y// and y// is parallel to x and y is perpendicular to x.

Homework Equations


x//y => x=ky
x.y=0 if x┴y

The Attempt at a Solution


I calculated the components of y along y and y// and showed that the synthesis of these gives y. I was adviced to use x as well. So I need different method.

By supposing y//=kx,
y=y-y//
we write,
kx.(y-y//)=0
and I was asked to find k and show,y=y + y//. I have no idea how to proceed after the above line.

Thank You
 
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Do you know how to project a vector onto another vector?
 
I was suggested not to use vector projections that are in trigonometric forms.
As for the y||=(x.y/x^2).x form,
I know that what I can do is find
y||=(y.kx/(kx)^2).kx [sorry, k is not bold here]
and yperp.=y-xk.,
I have no idea hence forth.
 
dpa said:
I was suggested not to use vector projections that are in trigonometric forms.
As for the y||=(x.y/x^2).x form,
.
This is what I meant by vector projection. In fact, you can take k = (x.y/x^2), can't you?
 

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