Vector Calculations | Find ⎮v-2w⎮

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SUMMARY

The discussion focuses on calculating the magnitude of the vector expression ⎮v - 2w⎮ given that ⎮v⎮=2, ⎮w⎮=3, and the angle between vectors v and w is π/3. The key equation to use is |v - 2w|² = (v - 2w)·(v - 2w), which simplifies the calculation by applying the properties of dot products and magnitudes. Participants emphasize the importance of utilizing the cosine of the angle to find the dot product, which is essential for solving the problem accurately.

PREREQUISITES
  • Understanding of vector magnitudes and operations
  • Familiarity with the dot product of vectors
  • Knowledge of trigonometric functions, specifically cosine
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study vector subtraction and its geometric interpretation
  • Learn how to apply the law of cosines in vector calculations
  • Explore the properties of dot products in vector analysis
  • Practice problems involving magnitudes and angles between vectors
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Students studying vector calculus, educators teaching physics or mathematics, and anyone looking to enhance their understanding of vector operations and calculations.

MozAngeles
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Homework Statement



If ⎮v⎮=2, ⎮w⎮=3, and the angle between v and w is [tex]\pi/3[\tex], find ⎮v-2w⎮.<br /> <br /> <h2>Homework Equations</h2><br /> <br /> Im not sure how to go about this. maybe use [tex]\cos\theta[\tex]=u∙v/⎮u⎮⎮v⎮<br /> <br /> <h2>The Attempt at a Solution</h2><br /> i'm not sure where to start. i know this has to be pretty straightforward, but i don't see it...<br /> anyt help would be nice thanks.[/tex][/tex]
 
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Hi MozAngeles! :smile:

(write /tex not \tex :wink:)

hint: |v - 2w|2 = (v - 2w).(v - 2w) :wink:
 

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