Undergrad Vector calculus identity format question

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The discussion centers on the identity involving the Laplacian operator applied to a vector field, specifically the relationship between the Laplacian of a vector field and its magnitude. The user seeks clarification on the correct form of the identity, which is noted as ##\nabla^2 \vec A = \nabla^2 A##. References to the vector Laplacian and scalar Laplacian are provided for further context. Additionally, there is a suggestion to express the vector in terms of its magnitude and a unit vector, which may complicate the resulting Laplacian expression. The conversation emphasizes the complexity of deriving a neat form for the Laplacian in this context.
kent davidge
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I know there is an identity involving the Laplacian that is like ##\nabla^2 \vec A = \nabla^2 A## where ##\vec A## is a vector and ##A## is its magnitude, but can't remember the correct form. Does anyone knows it?
 
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If you were so inclined you could set ##\vec{A}=|\vec{A}|\hat{n}##, then churn out how the Laplacian looks in terms of various derivatives of ##|\vec{A}|## and ##\hat{n}##. I don't think you will get anything pretty.
 
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There's a vector identity with the vector laplacian here:

https://mathworld.wolfram.com/VectorLaplacian.html

NumberedEquation1.gif
 
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