An electron in a magnetic field B=2.0T(ex-ez) has velocity v=(2.5x107 ms-1 (ex-ey)
a) calculate magnetic force on electron at that instant
b) what is the magnitude of this force
I am using the Lorentz force law.
F = q(vXB)
& evaluating the directions by vector
My argument is that the ey term is negative, but another person evaluates this as positive. Please confirm whether I'm right or wrong.
This affects the outcome of magnitude of force, too.
The Attempt at a Solution
F = -e 2(2.5x107) (ex-ez)* (ex-ey)
I ex ey ez I
I 1 . -1 . 0 I
I 1 . 0 . -1 I
= ex((-1x-1)-(0x0)) + ey((1X-1)-(0x1)) + ez ((1x0)-(-1x1))
= ex - ey + ez)
F = -8x10-12 (ex - ey + ez)