Vector evaluation & Lorentz force law

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Homework Help Overview

The problem involves calculating the magnetic force on an electron moving in a magnetic field, specifically using the Lorentz force law. The magnetic field and velocity vectors are provided, and the discussion centers around the evaluation of the cross product and the resulting force vector.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the Lorentz force law and evaluate the cross product of the velocity and magnetic field vectors. There is a question regarding the sign of the j term in the resulting force vector, with some participants suggesting a re-evaluation of the determinant used in the calculation.

Discussion Status

The discussion has seen some clarification regarding the sign of the terms in the force vector calculation. One participant acknowledges an oversight in their evaluation, indicating a productive exchange of insights. However, there is no explicit consensus on the final outcome of the force calculation.

Contextual Notes

Participants are navigating the complexities of vector evaluation, particularly in the context of cross products, and are addressing potential errors in sign that could affect the final result. The conversation reflects the iterative nature of problem-solving in physics.

Roodles01
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Homework Statement


An electron in a magnetic field B=2.0T(ex-ez) has velocity v=(2.5x107 ms-1 (ex-ey)
a) calculate magnetic force on electron at that instant
b) what is the magnitude of this force

Homework Equations


I am using the Lorentz force law.
F = q(vXB)
& evaluating the directions by vector

My argument is that the ey term is negative, but another person evaluates this as positive. Please confirm whether I'm right or wrong.

This affects the outcome of magnitude of force, too.

The Attempt at a Solution


F = -e 2(2.5x107) (ex-ez)* (ex-ey)

I ex ey ez I
I 1 . -1 . 0 I
I 1 . 0 . -1 I

= ex((-1x-1)-(0x0)) + ey((1X-1)-(0x1)) + ez ((1x0)-(-1x1))
= ex - ey + ez)

so
F = -8x10-12 (ex - ey + ez)
 
Physics news on Phys.org
Better believe your friend about the sign of the j term! (Re-check your determinant).
 
Last edited:
Ah! Having looked at it, I found that I didn't change the sign for the second term.
So simple it's annoying.
Thank you.
 
Roodles01 said:
Ah! Having looked at it, I found that I didn't change the sign for the second term.
So simple it's annoying.

Welcome to the club! :smile:
 

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