Vector expressions - equivalence

Click For Summary
SUMMARY

The discussion focuses on resolving the vector expressions related to the velocity of wind with respect to a moving car. The two expressions presented are: Expression 1 (vwg = vwc + vcg) and Expression 2 (vwc = vwg - vcg). Both expressions yield a wind magnitude of approximately 14 m/s, but differ in direction due to the observer's frame of reference. The confusion arises from the interpretation of vector directions, particularly regarding whether the wind appears to come from the front or behind the car.

PREREQUISITES
  • Understanding of vector quantities and their representations
  • Familiarity with basic trigonometry, specifically tangent functions
  • Knowledge of relative motion concepts in physics
  • Ability to construct and interpret vector diagrams
NEXT STEPS
  • Study vector addition and subtraction in physics
  • Learn about relative velocity and its applications
  • Explore trigonometric functions and their use in vector analysis
  • Practice constructing vector diagrams for various motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators seeking to clarify concepts of relative motion and vector representation.

jemerlia
Messages
28
Reaction score
0

Homework Statement


A car is traveling at 12ms^-1. To the passenger in the car the wind appears to be blowing at 8.0ms^-1 at right angles to the road. What is the magnitude and direction of the velocity of the wind with respect to the ground.


Homework Equations


I can think of two possible vector expressions which should be equivalent. I am clearly doing something wrong because they are not.
Using:
vwg = velocity of wind wrt ground
vcg = velocity of car wrt ground
vwc = velocity of wind wrt car
Expression 1
vwg = vwc + vcg

Expression 2 (following the rule of subtracting the observer's movement)
vwc= vwg-vcg

Yes - I'm aware I should add the negative vector and that the negative sign means the reverse direction

The Attempt at a Solution



Expression 1:
The solution vector diagram is (excuse the dots so I don't lose the spaces):

^----------->vcg
|.....^
|vwc ... /
|... / vwg
|.../
|../
|/
It gives a vwg magnitude of c. 14ms^-1 and a direction of tan^-1(8/12) = c. 34 degrees with the wind coming from behind the car

Expression 2:
The solution vector diagram is:

<----------------- -vcg
.^......^
...\......|
...\ ...| vwc
...vwg..\....|
.....\...|
.....\...|
......\..|
.....\|
Of course the magnitude is the same as in the previous example but the direction is
tan^-1 (8/-12) = -34 degrees.

My concern is that the wind appears to be coming from the front!

Gloom - what have I misunderstood?
 
Physics news on Phys.org
Your method is correct. The answer is not exactly 14m/s. In both cases it is only the direction you start with that results in the -ive or +ive sign. Why do you think the wind appears to be coming from the front?
 
Thank you for your reassurance. I lacked the confidence to be certain the second vector diagram was the equivalent of the first - especially because vector arithmetic is new to me. I would like to ask this naive question - if a, b and c are vector quantities and they are related:
a = b+c
then is it correct to transpose so that:
b= a-c
?

Why did I think the wind was coming from the front? The honest answer is twofold: first: sometimes I have a pathological inability to imagine the behaviour of the real word and, second I had convinced myself the second expression/vector diagram was telling a different story to the first.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
7K
  • · Replies 38 ·
2
Replies
38
Views
4K