Vector functions traveling along space curves

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SUMMARY

The discussion focuses on determining whether two particles traveling along the space curves defined by r1(t) = and r2(t) = <1 + 2t, 1 + 6t, 1 + 14t> collide or intersect. It is established that r2 passes through the point (1, 1, 1) and is parallel to the vector <2, 6, 14>, while r1 passes through the origin. The key conclusion is that the particles collide if there exists a common time t such that r1(t) = r2(t), and their paths intersect if there are distinct times t1 and t2 such that r1(t1) = r2(t2>.

PREREQUISITES
  • Understanding of vector functions and their representations
  • Knowledge of limits and continuity in calculus
  • Familiarity with the concept of parameterization in space curves
  • Ability to visualize and interpret geometric trajectories in three-dimensional space
NEXT STEPS
  • Explore the concept of parameterization in vector calculus
  • Study the conditions for collision and intersection of space curves
  • Learn about the geometric interpretation of vector functions
  • Investigate the use of limits in analyzing the behavior of vector functions
USEFUL FOR

Students studying calculus, particularly those focusing on vector functions and space curves, as well as educators seeking to enhance their teaching methods in this area.

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Homework Statement



two particles travel along the space curves r1(t)=<t, t2, t3> r2=<1+2t, 1+6t, 1+14t>
Do the particles collide? Do their paths intersect?

2. Homework Equations

if vector r(t)=<f(t), g(t), h(t)>, then
lim r(t) t-->a = <lim f(t)t-->a, lim g(t)t-->a, lim h(t)t-->a> provided the limits of the component functions exist.

The Attempt at a Solution



Vector r2 passes through the point (1, 1, 1) and is parallel to the vector <2, 6, 14> which I do not believe is going to be parallel to vector r1. I know that r1 passes through the origin though.
 
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Start with this: never in your problem it is said that t is time. It is important to know whether t is a common time or just a parameter. Suppose it is time. Then they collide if there is t such that both are at the same place: r1(t)=r2(t). Their trajectories intersect if there is place in space that is visited by both particles, perhaps at different time for each particle: r1(t1)=r2(t2). Now draw it, imagine, and think what to do next.
 

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