Vector identities in index notation

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SUMMARY

The discussion focuses on proving the vector identity using index notation: (del x f del g) = del f x del g. Participants explore the representation of the left-hand side (LHS) and right-hand side (RHS) in index notation, specifically using the Levi-Civita symbol (εijk) and partial derivatives (∂). The correctness of expressions involving the dot product and cross product in index notation is confirmed, emphasizing the relationship between the components of vectors A and B.

PREREQUISITES
  • Understanding of vector calculus and vector identities
  • Familiarity with index notation and the Levi-Civita symbol (εijk)
  • Knowledge of partial derivatives and their notation (∂)
  • Basic concepts of cross products and dot products in vector algebra
NEXT STEPS
  • Study the properties of the Levi-Civita symbol in tensor calculus
  • Learn about vector identities in three-dimensional space
  • Explore advanced applications of index notation in physics
  • Investigate the implications of vector calculus in fluid dynamics
USEFUL FOR

Students of physics and mathematics, particularly those studying vector calculus, as well as researchers and educators looking to deepen their understanding of vector identities in index notation.

trv
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Homework Statement



Prove using index notation that,

the x denoting a cross-product.

(del x f del g)=del f x del g


Homework Equations





The Attempt at a Solution



dif etc. denote partial derivatives.

RHS=eijkdjfdkg

LHS-I'm not even quite sure how to write it in index notation. Here's my attempt however.

LHS=eijk dj (fdkg)

But then if I write it like that, I can't tell the difference between LHS and RHS.

--------------------------------------------------------------------------------------------------

Also can someone check whether the following are correct,

A.B=AiBi=AiBi

(A x B)i=eijkAjBk
 
Last edited:
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Hint: εijkjkg = -εikjkjg = -εijkjkg

trv said:
Also can someone check whether the following are correct,

A.B=AiBi=AiBi

(A x B)i=eijkAjBk

Yes, that's correct.
 

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