Del operator crossed with a scalar times a vector proof

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Homework Help Overview

The discussion revolves around proving an identity involving the "Del" operator crossed with a scalar multiplied by a vector, specifically using summation convention notation. The identity in question is related to vector calculus and involves concepts such as the gradient and curl.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to break down the expression using Levi-Civita symbols but expresses confusion about the initial steps and the decomposition of the cross product. Some participants suggest including the j-th component of the vector in the expression. Others reference standard forms seen in textbooks and mention applying the product rule for differentiation as a next step.

Discussion Status

The discussion is ongoing, with participants providing guidance on the next steps, such as applying the product rule and reconstructing vectors from their components. There is an acknowledgment of the original poster's uncertainty regarding the proof process.

Contextual Notes

Participants note that the proofing process is new to the original poster, which may contribute to the confusion regarding the application of mathematical concepts and notation.

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"Del" operator crossed with a scalar times a vector proof

Homework Statement


Prove the following identity (we use the summation convention notation)

\bigtriangledown\times(\phi\vec{V})=(\phi \bigtriangledown)\times\vec{V}-\vec{V}\times(\bigtriangledown)\phi

Homework Equations



equation for del, the gradient, curl..

The Attempt at a Solution



im kind of confused on the first step...I broke it down into the following; however, levi civita symbols aren't my cup of tea and I get pretty confused about it...anyway here's what I did:

\bigtriangledown\times(\phi\vec{V})=(\epsilon_{ijk})\partial_i\vec{V}\phi\hat{x}_k

I don't know if this first step is right or if I decomposed the cross product right ?
 
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You should have the j:th component of V in your expression,
\nabla \times (\phi \vec{V}) = \epsilon_{ijk} \partial_i (\phi V_j) \hat{x}_k
 


The form you've written is completely equal to the one seen in math/physics books

\nabla\times \left(\phi\vec{V}\right) = \nabla\phi\times\vec{V} + \phi\nabla\times\vec{V}
 


Thanks for the replies, I'm just not sure what to do after what clamtrox said to do, the whole proofing business if pretty new to me :/
 


You need two more steps. Apply the product rule for differentiation and then once you obtain a sum of two terms, reconstruct vectors from their components.
 

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