Vectors plane question using components

In summary, a vector in a plane is a mathematical quantity with both magnitude and direction, represented by an arrow. Its components are the horizontal and vertical magnitudes, typically denoted by x and y. The magnitude can be found using the Pythagorean theorem and the direction can be negative if measured in a clockwise direction. To add or subtract vectors, their components are added or subtracted separately.
  • #1
KL90
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0

Homework Statement



An airplane wishes to fly from A to B which is located 1000 km northeast of A.
The maximum speed of the plane in still air is 650 km/hr.
There is a wind blowing West of 40 km/hr
In what direction should the pilot steer the plane to complete the trip as fast as possible?

Homework Equations




The Attempt at a Solution



I drew a diagram where an arrow from origin is 45 degrees above the east axis. Then at the head of that arrow is the head of the west arrow pointing west. and the two tails are connected for the plane's direction with the unknown angle between the plane velocity and the east axis.

velocity of plane in still air (vp)= 650(cos θ, sin θ)
velocity of wind (vw)= (-40, 0)
total velocity = |vtot| (cos 45, sin 45) = vp + vw
where |vtot| is the magnitude of the total velocity

Computing x component gives me:
|vtot| cos 45 = 650cosθ - 40

Computing y component give me:
|vtot|sin45 = 650sinθ

I've isolated for |vtot| but i don't know what to do after that.
 
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  • #2
Computing x component gives me:
|vtot| cos 45 = 650cosθ - 40

Computing y component give me:
|vtot|sin45 = 650sinθ
Put the two together to get (since sin 45 = cos 45):
650cosθ - 40 = 650sinθ

That boils down to sin θ - cos θ = -.0615
A bit awkward, isn't it?
You could graph sin θ - cos θ and look for when the y coordinate is -.0615.

You know, it looks kind of like the right side of
sin(a-b) = sin(a)*cos(b) - cos(a)*sin(b) with b = 45 degrees
sin(a-45) = sin(a)*cos(45) - cos(a)*sin(45)
sin(a-45) = cos(45)*[sin(a) - cos(a)]
[sin(a) - cos(a)] = sin(a-45)/cos(45)
 
  • #3
Is there any other way to compute without the use of graphing?

Could you explain further on why you use sin(a-b)?
 
  • #4
We have sin θ - cos θ = -.0615.
We can use the identity sin(a) - cos(a) = sin(a-45)/cos(45) to simplify this to: sin(θ-45)/cos(45) = -.0615
sin(θ-45) = -.0615*cos(45) = -.0435
θ-45 = arcsin(-.0435)
θ-45 = -2.49
θ = 42.5 degrees
It would be worth checking this with your x and y components 650cosθ - 40 and 650sinθ to see if they are equal (indicating NE for the total of the two velocity vectors)
 

1. What is a vector in a plane?

A vector in a plane is a mathematical quantity that has both magnitude and direction. It is represented by an arrow, with the length of the arrow representing the magnitude and the direction of the arrow indicating the direction of the vector.

2. What are the components of a vector in a plane?

The components of a vector in a plane are the horizontal and vertical magnitudes of the vector. They are usually represented by the letters x and y, respectively.

3. How do you find the magnitude of a vector in a plane using its components?

The magnitude of a vector in a plane can be found using the Pythagorean theorem. The magnitude is equal to the square root of the sum of the squares of the horizontal and vertical components.

4. Can the direction of a vector in a plane be negative?

Yes, the direction of a vector in a plane can be negative. The direction is determined by the angle between the vector and the positive x-axis. If the angle is measured in a counterclockwise direction, it is considered positive. If it is measured in a clockwise direction, it is considered negative.

5. How do you add or subtract vectors in a plane using components?

To add or subtract vectors in a plane, you simply add or subtract their horizontal and vertical components separately. The resulting vector will have a new set of components that represent the combined magnitudes and directions of the original vectors.

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