Vectors plane question using components

Click For Summary

Homework Help Overview

The problem involves an airplane's flight path from point A to point B, which is located 1000 km northeast of A. The airplane has a maximum speed of 650 km/hr in still air, and there is a wind blowing west at 40 km/hr. The objective is to determine the direction in which the pilot should steer the plane to complete the trip as quickly as possible.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of vector components to analyze the airplane's velocity in relation to the wind. The original poster attempts to isolate the total velocity and its components but expresses uncertainty about the next steps. Others suggest using trigonometric identities to simplify the equations and explore alternative methods for solving the problem without graphing.

Discussion Status

The discussion is ongoing, with participants sharing various approaches to the problem. Some have provided algebraic manipulations and identities to aid in the solution process, while others are seeking clarification on the reasoning behind certain steps. There is no explicit consensus yet, but productive lines of inquiry are being explored.

Contextual Notes

Participants are working under the constraints of the problem's parameters, including the specified wind speed and the maximum speed of the airplane. There is an emphasis on ensuring that the calculated direction aligns with the northeast destination.

KL90
Messages
7
Reaction score
0

Homework Statement



An airplane wishes to fly from A to B which is located 1000 km northeast of A.
The maximum speed of the plane in still air is 650 km/hr.
There is a wind blowing West of 40 km/hr
In what direction should the pilot steer the plane to complete the trip as fast as possible?

Homework Equations




The Attempt at a Solution



I drew a diagram where an arrow from origin is 45 degrees above the east axis. Then at the head of that arrow is the head of the west arrow pointing west. and the two tails are connected for the plane's direction with the unknown angle between the plane velocity and the east axis.

velocity of plane in still air (vp)= 650(cos θ, sin θ)
velocity of wind (vw)= (-40, 0)
total velocity = |vtot| (cos 45, sin 45) = vp + vw
where |vtot| is the magnitude of the total velocity

Computing x component gives me:
|vtot| cos 45 = 650cosθ - 40

Computing y component give me:
|vtot|sin45 = 650sinθ

I've isolated for |vtot| but i don't know what to do after that.
 
Physics news on Phys.org
Computing x component gives me:
|vtot| cos 45 = 650cosθ - 40

Computing y component give me:
|vtot|sin45 = 650sinθ
Put the two together to get (since sin 45 = cos 45):
650cosθ - 40 = 650sinθ

That boils down to sin θ - cos θ = -.0615
A bit awkward, isn't it?
You could graph sin θ - cos θ and look for when the y coordinate is -.0615.

You know, it looks kind of like the right side of
sin(a-b) = sin(a)*cos(b) - cos(a)*sin(b) with b = 45 degrees
sin(a-45) = sin(a)*cos(45) - cos(a)*sin(45)
sin(a-45) = cos(45)*[sin(a) - cos(a)]
[sin(a) - cos(a)] = sin(a-45)/cos(45)
 
Is there any other way to compute without the use of graphing?

Could you explain further on why you use sin(a-b)?
 
We have sin θ - cos θ = -.0615.
We can use the identity sin(a) - cos(a) = sin(a-45)/cos(45) to simplify this to: sin(θ-45)/cos(45) = -.0615
sin(θ-45) = -.0615*cos(45) = -.0435
θ-45 = arcsin(-.0435)
θ-45 = -2.49
θ = 42.5 degrees
It would be worth checking this with your x and y components 650cosθ - 40 and 650sinθ to see if they are equal (indicating NE for the total of the two velocity vectors)
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
2
Views
2K
Replies
3
Views
3K
Replies
1
Views
2K
Replies
3
Views
2K