The discussion revolves around a kinematics problem involving a moped's motion, as represented by a velocity versus time graph. Participants are tasked with sketching related graphs for position versus time and acceleration versus time, while also calculating specific values at given times.
There is an ongoing exploration of the equations for velocity across different segments of time. Participants are sharing calculations and questioning assumptions about slopes and intercepts. Some guidance has been provided regarding the integration of velocity to find position, but no consensus has been reached on all aspects of the problem.
Participants are working under constraints of homework rules that require sketching graphs by hand and providing numerical values for specific points. There is also a mention of potential confusion regarding the correct interpretation of graph segments and their respective areas.
veloix said:it should be the v(t).
veloix said:v(t) at t= 6.0s should be ∫v(t)dt
veloix said:when i intagrate that i get t^2/2?
veloix said:yea it comes out to be 18m/s but it wrong answer.
veloix said:t= 6 v(t)=6^2/2=18m/s
veloix said:oh that's why i got it wrong i had 2 written on my y-axis instead of 4, ugg. so to get the speed at 12s i would get area of each rectangle and add them up.
veloix said:great that work out perfectly thank you
part c asking for distance this time, the ∫d(t)?
veloix said:i can't draw this plot right I am haveing difficluty.