Velocity-Friction proportionality.

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The discussion focuses on calculating the time it takes for a 1000kg boat to slow to half its speed after its engine is shut off, with the frictional force proportional to the boat's speed at a constant of 70. Using Newton's second law, the retarding force is expressed as Fr = 70 * v, leading to the differential equation -dv/dt = 0.07 * v. By integrating this equation from the initial speed v to v/2, the time required for the boat to decelerate is determined, providing a clear solution to the problem.

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1. A 1000kg boat is traveling across a lake when its engine is shut off. The magnitude of the frictional force between the water and the boat is proportional to the boat's speed (proportionality constant is 70) . Find the time it takes the boat to slow to one half its speed when the engine was shut off.
2.Using Newton's second law: F=ma 3. I'm guessing the acceleration is not constant in this problem. So the constant acceleration equations don't apply. I don't know how to include the time in this problem if i have no equations to solve them in.
Thanx in advance.
 
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At any instant Fr = 70* v.
Or retarding force ar = 70/1000*v Or
-dv/dt = 0.07*v or
-(dv/v) = 0.07*dt.
Take the integration between v to v/2 and find t.
 
Thank you so much ! makes perfect sense now !
 

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