MHB Velocity & Horizontal Distance of Person on Water Slide

Click For Summary
To determine the velocity and horizontal distance of a person flying off a water slide ramp, the conservation of energy is the most suitable approach. By applying the equation T1 + V1 + U1 = T2 + V2, all relevant variables must be identified and substituted to solve for velocity. After calculating the velocity at the ramp's exit, projectile motion equations can be used to find the horizontal distance traveled. The initial velocity and angle of the ramp will be crucial for this calculation. This method effectively combines energy conservation with kinematic principles to solve the problem.
chunky
Messages
5
Reaction score
0
a person slides down a water slide that is 61 m long and has a slope angle of 24 degrees and the end is a ramp with a height of 3.66 m with an angle of 30 degrees to the horizontal determine the magnitude and direction of the velocity of the person when they just fly away from the ramp and the horizontal distance that they fly.

View attachment 2500
 

Attachments

Mathematics news on Phys.org
There are a number of equations that I like to say "have physics in them", as opposed to being merely descriptive. Your equations with physics, in a typical order of presentation, are the following:
  1. Newton's Second Law
  2. Conservation of Energy
  3. Work-Energy Theorem
  4. Conservation of Linear Momentum
  5. Conservation of Angular Momentum

Which of these approaches do you think would be appropriate for this problem?
 
I believe the most appropriate approach would be the conservation of energy ie,

T1+V1+U1-2=T2+V2

Then just find all of the relevant pieces of information from the question and subbing them into the equation and solving for the magnitude and direction of the velocity and well as the max flying distance
 
I would agree that CoE would be the right approach for the first part of this problem (finding the velocity). Once you do that, however, how would you continue?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
34
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
12
Views
532
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 32 ·
2
Replies
32
Views
3K