Velocity of an object on an inclined plane

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SUMMARY

The discussion centers on calculating the velocity of an object on an inclined plane using the work-energy theorem. The user initially derived an incorrect expression for velocity, resulting in a maximum speed of 10/6 instead of the correct 10/3. The error stemmed from neglecting to account for the variable friction force, which is defined as u=0.3x, where x is the distance traveled. After integrating the friction force correctly, the user arrived at the correct answer.

PREREQUISITES
  • Understanding of the work-energy theorem in physics
  • Knowledge of inclined plane dynamics
  • Familiarity with variable friction coefficients
  • Basic calculus for differentiation and integration
NEXT STEPS
  • Study the application of the work-energy theorem in variable force scenarios
  • Learn about inclined plane motion with varying friction coefficients
  • Explore advanced integration techniques for physics problems
  • Investigate the relationship between velocity and kinetic energy maximization
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators looking for examples of common errors in applying the work-energy theorem.

Prabs3257
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Homework Statement
A body starts from rest on a long incline plane of slope 45 degree the coefficient of friction between the body and the plane varies as u=0.3x where x is the distance traveled down the plane the body will have maximum speed when x is
Relevant Equations
Work energy theorem
I used work energy theorem between initial top point and point x along the incline(downwards) i got the expression of v then diffrentiated it to get a maxima but it gives me a wrong ans which is 10/6 but the actual ans is 10/3 please tell me what i did wrong
 

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Prabs3257 said:
Homework Statement:: A body starts from rest on a long incline plane of slope 45 degree the coefficient of friction between the body and the plane varies as u=0.3x where x is the distance traveled down the plane the body will have maximum speed when x is
Homework Equations:: Work energy theorem

I used work energy theorem between initial top point and point x along the incline(downwards) i got the expression of v then diffrentiated it to get a maxima but it gives me a wrong ans which is 10/6 but the actual ans is 10/3 please tell me what i did wrong

There is a simple approach to this problem. Hint: what can you say about the forces when the body reaches its maximum speed?
 
PeroK said:
There is a simple approach to this problem. Hint: what can you say about the forces when the body reaches its maximum speed?
Ya i first did it using forces only and got the correct answer but i want to know what i did wrong with this
 
Prabs3257 said:
Ya i first did it using forces only and got the correct answer but i want to know what i did wrong with this

You'd need to post your working. I'm not sure if it's worth it, though.
 
PeroK said:
You'd need to post your working. I'm not sure if it's worth it, though.
I did post an img of it in the ques
 
Prabs3257 said:
I did post an img of it in the ques
There's almost no working there at all. You have an expression for ##v(x)## that you haven't justified. Did you integrate the friction force down the slope?

PS It looks like you just mixed up a factor of ##\sqrt 2## at some point.
 
Prabs3257 said:
I did post an img of it in the ques

Here's a neat trick. Maximising ##v## is the same as maximising ##v^2##. That makes the differentiation easier.
 
PeroK said:
There's almost no working there at all. You have a very simple expression for ##v(x)## that you haven't justified and is wrong in any case. Did you integrate the friction force down the slope?
Oh sorry i just forgot f was not constant and i integrated it now and got the correct ans thanks
 

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