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I've been asked to solve for the initial velocity, (Vi), and the only known information is:

Vertical Acceleration = -9.81 m/s^2

Horizontal Displacement = 3.885m

Delta Y (Height Ball was launched above the ground) = 1.015m

Theta = 9 degrees

I'm not asking anyone to solve this for me, but I'm really stuck. I was wondering if anyone could tell me the steps I must do, or even better, an equation that I could use to solve this.

Any help is greatly appreciated.

Thank you.