Velocity of SHM Object at t=0.10s

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SUMMARY

The velocity of an object undergoing simple harmonic motion (SHM) at time t=0.10s is calculated using the formula v=A*√(K/m)*cos(√(K/m)*t). Given the parameters: mass (m) of 36.0g, spring constant (k) of 400g/s², and maximum displacement (A) of 5.0 cm, the velocity can be determined by substituting these values into the equation. This results in a definitive calculation of the object's velocity at the specified time.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with the concepts of mass, spring constant, and displacement
  • Knowledge of trigonometric functions, particularly cosine
  • Ability to perform calculations involving square roots and basic algebra
NEXT STEPS
  • Calculate the velocity of the SHM object using the provided formula with the given parameters
  • Explore the effects of varying mass and spring constant on SHM velocity
  • Investigate the relationship between amplitude and velocity in SHM
  • Learn about the energy transformations in simple harmonic motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to simple harmonic motion.

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Homework Statement


At time t, the velocity of v of an object undergoing simple harmonic motion at the end of a spring is given by the formula below. here m is mass of the object (in g), k is a constant depending on the spring (in g/s squared), a is the maximum distance the object moves and t is time (in s).

t=0.10s
m= 36.0g
k= 400g/s][2]
A= 5.0 cm

Homework Equations


v=A*√K/m*cos(√K/m *t)

The Attempt at a Solution

 
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