How do i get the frequency of undamped motion?

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Discussion Overview

The discussion revolves around calculating the frequency of undamped motion for a vertical spring system in an aircraft landing scenario. Participants explore the relationship between force, spring stiffness, mass, and frequency, while addressing the implications of the given parameters and initial conditions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a scenario involving a spring system with specific parameters, including force, spring stiffness, and damping coefficient.
  • Another participant suggests that the problem can be approached using a differential equation with initial conditions, prompting a check for any missing information.
  • A participant questions the realism of the mass derived from the force and gravitational acceleration, suggesting that 750 kg may be low for an aircraft wheel.
  • There is a correction regarding the spring stiffness, where one participant clarifies that the correct conversion from N/mm to Nm is necessary for accurate calculations.
  • Participants calculate the frequency of undamped motion using the formula fn = 1/2π * √(k/m), with differing values for stiffness leading to different frequency results.

Areas of Agreement / Disagreement

Participants express differing views on the realism of the mass calculation and the correctness of the spring stiffness conversion. There is no consensus on the final frequency value due to the variations in parameters used in calculations.

Contextual Notes

Participants note the importance of correctly converting units and the potential impact of initial conditions on the problem. The discussion highlights the need for clarity in assumptions regarding the system's parameters.

Who May Find This Useful

Students and enthusiasts interested in mechanics, particularly in the context of oscillatory motion and spring systems, may find this discussion relevant.

ThePeculiarEngineer

Homework Statement


The single wheel of an aircraft can undergo a max of 7500N at a vertical velocity of 8 m/s on landing. The vertical spring moves in SHM and has a stiffness of 600N/mm. The systems vertical damper has a damping coefficient of 38 x 10^3 Ns.m-1

Homework Equations


F=Kx
F=Kx+cv=ma
ω = √ k/m

The Attempt at a Solution


I've tried "F=Kx+cv=ma" but when i solve for "Kx+cv" I am not quite sure how to then solve for the mass. the question doesn't even give the mass
 
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Hello peculiar, :welcome:
Seems to me you have a differential equation with two initial conditions: ##x (=0)## and ##\dot x = 8 ## m/s

Show your work in detail and check if there is a given you haven't used (he said mysterically
 
BvU said:
Hello peculiar, :welcome:
Seems to me you have a differential equation with two initial conditions: ##x (=0)## and ##\dot x = 8 ## m/s

Show your work in detail and check if there is a given you haven't used (he said mysterically
Thank you for replying BvU

Ah I see, is x=0 because it is in the equilibrium position?
 
I expect you are allowed to call it that. I don't know how realistic this exercise is. 750 kg isn't much.
 
Hey, BvU how does this look?

F=7500
k=600Nmm=0.6Nm

m =F/g=7500/9.81=764.53kg

Frequency(fn) of undamped motion

fn=1/2pi *√ k/m
so...
fn=1/2pi *√ 0.6Nm/764.53Kg=4.45*10^-3 Hz
 
ThePeculiarEngineer said:
k=600Nmm=0.6Nm
Excuse me ? Could you check this thoroughly :rolleyes: ?
 
Ah sorry, here are the changes

F=7500
k=600Nmm=6*10^5Nm

m =F/g=7500/9.81=764.53kg

Frequency(fn) of undamped motion

fn=1/2pi *√ k/m
so...
fn=1/2pi *√ 6*10^5Nm/764.53Kg=4.45 Hz
 

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