Velocity of Sound, speed of rock and return of sound

Click For Summary
SUMMARY

The problem involves calculating the velocity of a rock thrown vertically towards a bell located 50 meters away, with the sound of the bell heard 4.5 seconds later. Given the speed of sound at 330 m/s, the time for sound to travel back is calculated as 0.1515 seconds. The time taken by the rock to reach the bell is determined by subtracting the sound travel time from the total time, resulting in a velocity of approximately 11.5 m/s for the rock. This calculation is essential for understanding the relationship between distance, time, and velocity in physics.

PREREQUISITES
  • Understanding of basic physics concepts such as velocity, distance, and time.
  • Familiarity with the equation d = v/t for calculating speed.
  • Knowledge of the speed of sound in air, specifically 330 m/s.
  • Ability to perform basic arithmetic operations and unit conversions.
NEXT STEPS
  • Study the principles of kinematics, focusing on motion in one dimension.
  • Learn about the speed of sound in different mediums and its implications in physics.
  • Explore more complex problems involving relative motion and sound travel time.
  • Practice using the equations of motion to solve real-world physics problems.
USEFUL FOR

This discussion is beneficial for students beginning their studies in physics, particularly those learning about motion, sound, and basic kinematic equations. It is also useful for educators looking for practical examples to illustrate these concepts.

Chrisss
Messages
1
Reaction score
0

Homework Statement


Rock is thrown vertically towards a bell 50m away, you hear the bell ring 4.5 seconds later, how fast was the rock travelling, assuming the speed of sound is 330m/s

Homework Equations


d=v/t

The Attempt at a Solution


I like to draw my questions out, then fill in the data, so i'll do that first, if you don't wish to see it please scroll down a bit
4.5 seconds for return of sound
<-----------------
--------------------bell
^Starting position 50m
Speed of sound 330m/s
Distance 50m
4.5 seconds for sound to return from throwing it

Now, first I wanted to find how long it would take the sound to get back after it hit the bell so I looked for time
T = D/V

T=50m / 330mps
0.15151515s

I then tried to find the velocity it would take for the rock to reach the bell on it's own,
so I looked for the time again, from which I could distract the time it took for the sound from

V = D/T
V = 50m / 4.5s
V = The rock was going for 11.11111mps IF the sound was instantaneous, I've no idea how to subtract 0.15151515s from 11.11111mps

I don't know if I missed something during instruction, but I've just started physics and this could be stupid, but I've no clue where to go from here.

The answer for checking your answer is 11.5mps
 
Physics news on Phys.org
hi Chrisss, welcome to PF.
Time taken by the stone to strike the bell is ( 4.5 - 0.1515) s
Now find the velocity of the stone.
 

Similar threads

Solving for Time to Reach Ground: Calculating Velocity of Sound over 50m
  • · Replies 2 ·
Replies
2
Views
2K
Can You Calculate the Rock's Speed Without Considering Sound Delay?
  • · Replies 4 ·
Replies
4
Views
3K
Questioning the Solution for Elevator vs Rock Problem
  • · Replies 7 ·
Replies
7
Views
2K
Solving Symbolically: Height of Cliff with No Air Resistance
  • · Replies 1 ·
Replies
1
Views
1K
Rock falls from cliff-Initial Velocity?
  • · Replies 3 ·
Replies
3
Views
2K
Projectile Motion Kinematics: A catapult launches a rock....
  • · Replies 5 ·
Replies
5
Views
4K
Rock off cliff - calculate height by using speed of sound
  • · Replies 2 ·
Replies
2
Views
6K
Velocity Formulas for Projectile Motion
  • · Replies 10 ·
Replies
10
Views
3K
How Do You Calculate the Final Velocity of a Projectile?
  • · Replies 1 ·
Replies
1
Views
2K
Initial Position Discrepancy Involving Fluid Resistance
  • · Replies 5 ·
Replies
5
Views
2K