Vertical Component of this Picture?

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To find the vertical component of the ball's velocity when it reaches the fence, the initial vertical velocity can be calculated using the formula v_y = v * sin(θ), where v is the initial velocity (17 m/s) and θ is the angle (52°). This results in a vertical velocity of approximately 13.2 m/s at launch. As the ball ascends, it will experience a downward acceleration due to gravity (9.8 m/s²), which affects its vertical velocity as it travels. The vertical component at the fence can be determined by subtracting the gravitational effect over the time it takes to reach the fence. The final answer should be expressed in m/s, ensuring clear calculations are shown for better understanding.
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A ball of mass 0.6 kg, initially at rest, is
kicked directly toward a fence from a point
20 m away, as shown below.
The velocity of the ball as it leaves the
kicker’s foot is 17 m/s at angle of 52◦
above
the horizontal. The top of the fence is 7 m
high. The ball hits nothing while in flight and
air resistance is negligible.
The acceleration due to gravity is 9.8 m/s

What is the vertical component of the velocity
when the ball reaches the plane of the fence?
Answer in units of m/sI've tried -1.764

Untitled-1.png


Problem 20 using picture
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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