The problem involves calculating the vertical force exerted on the road by each wheel of a truck carrying a load, with a total mass of 28000 kg. The context includes the use of Newton's second law, F=ma, to determine the force based on mass and gravitational acceleration.
Some participants have provided guidance on the method of calculation, suggesting that finding the total mass and converting it to weight before dividing by four is a reasonable approach. There is an ongoing exploration of the calculations and assumptions, particularly regarding the representation of numbers in scientific notation.
There is a noted confusion regarding the representation of numbers in scientific notation, which may affect the calculations. Additionally, a new question about the effective thrust of a lorry starting from rest has been introduced, indicating a shift in the discussion focus.
Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.fleur said:Homework Statement
A truck (mass 1.2 x 104 kg) carries a load of 1.6 x 104 kg. What vertical force is exerted on the road by each wheel assuming the mass is uniformly spread?
Homework Equations
F=ma[/B]The Attempt at a Solution
1.2 x 104 kg+1.6 x 104 kg=291.2kg total mass
291.2/4=72.8kg to get mass on each wheel[/B]
F=ma 72.8kgx9.81=714 N
I have made the changes is the method i used correct though?gneill said:Those numbers in the problem statement are given using scientific notation, although the powers of ten are missing the superscript for the exponents. So for the truck mass, for example, 1.2 x 104 kg should read: 1.2 x 104 kg, which is equivalent to 12000 kg.
Fix your starting numbers accordingly and retry your calculations.
The method is okay and will deliver the correct result.fleur said:I have made the changes is the method i used correct though?
Please start a new thread for a new question.fleur said:I have another question and I have no clue on how to attempt this one
The lorry starts from rest with an acceleration of 2 ms-2.
What is the effective thrust is being exerted?