A 1.00 kg block is compressed a distance of x = 0.130 m against a vertical massless spring with spring constant 280 N/m. The block is released from rest. How far above the spring's equilibrium point does the block travel? I used conservation of energy and got 0.5kx^2 + 0.5mv^2 + mgh = 0.5kX^2 + 0.5mV^2 + mgH 0.5(280)(0.13^2) + 0 + 0 = 0 + 0 + (1)(9.8)H 2.366 = 9.8H H= 0.2414 This is marked wrong so i thn subtracted the initial 0.13 and it was still marked wrong. Can anyone tell me why and how to do it? Please?