A 1.00 kg block is compressed a distance of x = 0.130 m against a vertical massless spring with spring constant 280 N/m. The block is released from rest. How far above the spring's equilibrium point does the block travel?(adsbygoogle = window.adsbygoogle || []).push({});

I used conservation of energy and got

0.5kx^2 + 0.5mv^2 + mgh = 0.5kX^2 + 0.5mV^2 + mgH

0.5(280)(0.13^2) + 0 + 0 = 0 + 0 + (1)(9.8)H

2.366 = 9.8H

H= 0.2414

This is marked wrong so i thn subtracted the initial 0.13 and it was still marked wrong.

Can anyone tell me why and how to do it? Please?

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# Homework Help: Vertical mass less spring problem

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