Vertical Motion Homework Problem

  • Thread starter rg3po
  • Start date
  • #1
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Homework Statement


A rock is thrown vertically upward from the edge of a cliff. The rock reaches a maximum height of 18.6 m above the top of the cliff before falling to the base of the cliff, landing 6.60 s after it was thrown. How high is the cliff? Assume gravity= 9.8m/s2


Homework Equations


Vyf=Vyo + at
Y=Yo + 1/2(Vyo+Vyf)t
Y=Yo + Vyot + 1/2at2
Vyf2=Vyo2+ 2a(y-yo)



The Attempt at a Solution


I don't know where to start. I must figure out initial speed and the difference between the cliff and the max height. Is the initial position 0 at the height of the cliff or at the max height? Do I care that when the ball reaches the max height the speed is 0?


EDIT:Figured it out, I had the dumb for few minutes
 
Last edited:

Answers and Replies

  • #2
1,065
10
Solve it graphically, velocity vs. time.
 

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