Vertical rise of liquid at the back of a linearly accelerating tank....

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Homework Help Overview

The discussion revolves around the vertical rise of liquid in a tank that is linearly accelerating. Participants are examining the relationship between the acceleration of the tank and the resulting liquid surface rise, questioning the validity of a specific formula presented in the notes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the formula provided for the vertical rise, specifically the terms involved and their physical meaning. There is a focus on the implications of setting the acceleration to zero and the dimensional consistency of the expression.

Discussion Status

The discussion is active, with participants raising concerns about the formula's validity and dimensional consistency. Some are challenging the assumptions made in deriving the formula, while others are defending their interpretations.

Contextual Notes

There is an ongoing debate about the dimensional consistency of the expressions used, and the implications of different acceleration values on the formula's applicability. Participants are navigating through these assumptions without reaching a consensus.

hotjohn
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Homework Statement


why the vertical rise of the surface is given by the formula as shown in the notes ? shouldn't it = Δs =
(g +az ) Δx / ax ?

Homework Equations

The Attempt at a Solution

 

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hotjohn said:
(g +az ) Δx / ax ?
No, it can't be that. Consider ax=0.
How did you arrive at that?
 
Another issue is that your expression is dimensionally inconsistent.
 
gleem said:
Another issue is that your expression is dimensionally inconsistent.
No, I don't think so. az is supposed to be az, an acceleration, etc.
 

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