Very basic, short impulse problem. Just need some explanation.

In summary, the magnitude of the impulse that the sun applies to the Earth during six months is equal to 2P. This is due to the change in direction of the Earth's momentum over the six month period, from P to -P. It is important to understand that impulse is equal to the change in momentum, and to not confuse the absolute value of ΔP with Δ|P|.
  • #1
AATroop
31
2

Homework Statement


If the magnitude of the Earth's momentum is P, what is the magnitude of the impulse that the sun applies to the Earth during six months?


Homework Equations





The Attempt at a Solution


I know the solution is 2P, and I'm pretty sure it's just due to the change in direction that would occur when looking at the different time steps; when t =0, the Earth (we can assume) is moving in the positive x direction, and at t= 6 months, the Earth is moving in the negative x direction, so | m*(-v) - m*v | = 2mv or 2P. Is this adequate?
 
Physics news on Phys.org
  • #2
Sounds like you understand it just fine. The key physics is understanding that impulse = Δmomentum. And that the momentum of the Earth changes from P to -P over six months.
 
  • #3
Doc Al said:
Sounds like you understand it just fine. The key physics is understanding that impulse = Δmomentum. And that the momentum of the Earth changes from P to -P over six months.

OK, thanks. Just wanted to be sure, because I often confuse |ΔP| with Δ|P|.
 

1. What is a "very basic, short impulse problem"?

A "very basic, short impulse problem" is a type of physics problem that involves calculating the change in momentum of an object after experiencing a short burst of force. This type of problem is typically seen in introductory physics courses and can involve various scenarios such as collisions or explosions.

2. How do you calculate the change in momentum for a short impulse problem?

To calculate the change in momentum, you can use the formula Δp = FΔt, where Δp is the change in momentum, F is the force applied, and Δt is the duration of the impulse. This formula is based on the principle of impulse and momentum, which states that the change in momentum of an object is equal to the force applied multiplied by the duration of the force.

3. What are some real-life examples of short impulse problems?

Short impulse problems can be seen in various real-life scenarios such as a car crash, a ball bouncing off a wall, or a rocket launching into space. In each of these situations, there is a short burst of force that causes a change in the momentum of an object.

4. What are the units for momentum and force in a short impulse problem?

The units for momentum are typically kg·m/s, while the units for force are typically N (newton). However, it is important to check the specific problem and make sure all units are consistent before solving.

5. How can understanding short impulse problems be useful in the real world?

Understanding short impulse problems can be useful in many real-world applications, such as engineering, sports, and transportation. For example, engineers use the principles of impulse and momentum to design safer cars and buildings. Athletes also use these principles to improve their performance, such as in throwing or jumping events. Additionally, understanding short impulse problems can help us better understand and predict the motion of objects in daily life.

Similar threads

  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
13
Views
6K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
7
Views
3K
  • Introductory Physics Homework Help
Replies
24
Views
2K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
30
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
2K
Back
Top