Very brief explanation please? - Newt 2nd Law w/ Circular Motion

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SUMMARY

The discussion revolves around the radial acceleration of a weight in a conical pendulum setup. The user initially confused the forces involved, questioning why T*sin(θ) is used instead of T*cos(θ) for calculating radial acceleration. The correct approach is confirmed as T*sin(θ) being the force component that acts perpendicular to the radial direction, thus providing the necessary radial acceleration. The user later realizes their mistake, clarifying that they were thinking of a standard 2-D pendulum instead of the conical variant.

PREREQUISITES
  • Understanding of conical pendulum dynamics
  • Basic knowledge of trigonometric functions (sine and cosine)
  • Familiarity with Newton's laws of motion
  • Concept of radial acceleration in circular motion
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  • Study the dynamics of conical pendulums in detail
  • Learn about the derivation of radial acceleration in circular motion
  • Explore the application of trigonometric functions in physics problems
  • Investigate the differences between conical and simple pendulums
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Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of circular motion and pendulum dynamics.

mc8569
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Consider a conical pendulum with a weight on it and that makes some angle with the vertical. I am told to find the radial acceleration of the weight and someone showed me how it is solved but I don't understand why:

I am told to set

Tsin@ = m(ar) *ar = radial acceleration
ar = (Tsin@)/m

I was wondering why it would be T*SIN* instead of T*COS*? Tcos@ would give you the force that is parallel with radial acceleration, Tsin@ gives you a force that is perpendicular to the radial acceleration... Please help me! I don't understand this - only should take a few seconds. Thanks! XP
 
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AHHHH OHHH NEVERMIND! Sorry... *CONICAL* pendulum, lol I was thinking of a regular, 2-D pendulum. I would delete this if I could, but I can't =\ But no need to respond anyone! So silly!
 

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