Very obscure/confusing question on quiz today

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Frosteh
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Homework Statement


This is exactly how this was written on the quiz today:

If f(1)=1 and f'(x)=(1/3) when x=1, find d/dx[f(2x2-x)].

Homework Equations



Basic derivative rules (i.e., power rule).

The Attempt at a Solution



The first statement simply determines that f(2x2-x) is true. When taking the derivative of f(2x2-x), you get 4x-1. However, f'(1)=(1/3). When 1 is entered into 4x-1, (1/3) is clearly not the answer. I listed my answer as 12x-3, by setting 4x-1=(1/3), but I'm not sure if this is correct.

Is my professor insane or is this just a trickily worded question?
 
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Frosteh said:

Homework Statement


This is exactly how this was written on the quiz today:

If f(1)=1 and f'(x)=(1/3) when x=1, find d/dx[f(2x2-x)].

Homework Equations



Basic derivative rules (i.e., power rule).

The Attempt at a Solution



The first statement simply determines that f(2x2-x) is true.
No, not at all. A function value is not something that is true or false.
Frosteh said:
When taking the derivative of f(2x2-x), you get 4x-1.
No, that is incorrect, as pointed out by SteamKing in another post. You need to use the chain rule to evaluate d/dx( f(2x2 - x)).
Frosteh said:
However, f'(1)=(1/3). When 1 is entered into 4x-1, (1/3) is clearly not the answer. I listed my answer as 12x-3, by setting 4x-1=(1/3), but I'm not sure if this is correct.

Is my professor insane or is this just a trickily worded question?
 
Mark44 said:
You need to use the chain rule to evaluate d/dx( f(2x2 - x)).

Mark44 is of course correct, but enough is known in this question not to require doing that.
 
There is ambiguity in how one uses language, necessary ambiguity I think, that one cannot avoid. One must be charitable (see Quine, Indeterminacy of translation) when interpreting the words of others.

And on forums this is a bigger problem, of course. I hope what I intended is clear, that one has quite detailed knowledge of f(x).