Very obscure/confusing question on quiz today

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Homework Help Overview

The problem involves finding the derivative of a composite function, specifically d/dx[f(2x^2-x)], given certain values of the function and its derivative at a specific point. The context suggests a focus on the application of derivative rules, particularly the chain rule.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the necessity of using the chain rule for differentiation and question the original poster's interpretation of the problem. There are attempts to clarify the correct approach to taking the derivative and to address potential misunderstandings of the function's properties.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the need for the chain rule while others express confusion about the original poster's reasoning. There is a recognition of the complexity of the question, and multiple interpretations of the problem are being explored.

Contextual Notes

There is mention of potential ambiguity in the wording of the question and the assumptions made by the original poster regarding function values and derivatives. The discussion reflects on the clarity of communication in mathematical contexts.

Frosteh
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Homework Statement


This is exactly how this was written on the quiz today:

If f(1)=1 and f'(x)=(1/3) when x=1, find d/dx[f(2x2-x)].

Homework Equations



Basic derivative rules (i.e., power rule).

The Attempt at a Solution



The first statement simply determines that f(2x2-x) is true. When taking the derivative of f(2x2-x), you get 4x-1. However, f'(1)=(1/3). When 1 is entered into 4x-1, (1/3) is clearly not the answer. I listed my answer as 12x-3, by setting 4x-1=(1/3), but I'm not sure if this is correct.

Is my professor insane or is this just a trickily worded question?
 
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What happens if you take the derivative of f(2x^2-x) with respect to x? (Don't worry about substituting the values f(1) and f'(1) at this stage.
 
This is a moderately tricky but well-phrased question. But I think perhaps you do not understand it?
 
Frosteh said:

Homework Statement


This is exactly how this was written on the quiz today:

If f(1)=1 and f'(x)=(1/3) when x=1, find d/dx[f(2x2-x)].

Homework Equations



Basic derivative rules (i.e., power rule).

The Attempt at a Solution



The first statement simply determines that f(2x2-x) is true.
No, not at all. A function value is not something that is true or false.
Frosteh said:
When taking the derivative of f(2x2-x), you get 4x-1.
No, that is incorrect, as pointed out by SteamKing in another post. You need to use the chain rule to evaluate d/dx( f(2x2 - x)).
Frosteh said:
However, f'(1)=(1/3). When 1 is entered into 4x-1, (1/3) is clearly not the answer. I listed my answer as 12x-3, by setting 4x-1=(1/3), but I'm not sure if this is correct.

Is my professor insane or is this just a trickily worded question?
 
Mark44 said:
You need to use the chain rule to evaluate d/dx( f(2x2 - x)).

Mark44 is of course correct, but enough is known in this question not to require doing that.
 
? How can you possibly evaluate d/dx(f(2x^2- x) without using the chain rule?
 
There is ambiguity in how one uses language, necessary ambiguity I think, that one cannot avoid. One must be charitable (see Quine, Indeterminacy of translation) when interpreting the words of others.

And on forums this is a bigger problem, of course. I hope what I intended is clear, that one has quite detailed knowledge of f(x).
 

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