- #1
James889
- 192
- 1
Hi,
I have didn't have an answer to this, so i need someone to tell me whether my work is correct or not.
This is the circuit:
[PLAIN]http://img251.imageshack.us/img251/4081/circuit1.png
I need to determine the current I.
Remove the first source and calculate the current provided by the other.
[PLAIN]http://img255.imageshack.us/img255/1665/circuit11.png
The total resistance is 150ohm [tex]100 + \frac{100 \cdot 100}{100+100}[/tex]
I = 10/150 ~0.067A
And the current through the resistor is:
[tex] \frac{100}{200} \cdot 0.067 = 33,5mA[/tex]
Do the same with the other source
[PLAIN]http://img69.imageshack.us/img69/9727/circuit12.png
I = 5/150 ~0.033A
[tex] \frac{100}{200} \cdot 0.033 = 16,5mA[/tex]
So the current I should be 50mA
I have didn't have an answer to this, so i need someone to tell me whether my work is correct or not.
This is the circuit:
[PLAIN]http://img251.imageshack.us/img251/4081/circuit1.png
I need to determine the current I.
Remove the first source and calculate the current provided by the other.
[PLAIN]http://img255.imageshack.us/img255/1665/circuit11.png
The total resistance is 150ohm [tex]100 + \frac{100 \cdot 100}{100+100}[/tex]
I = 10/150 ~0.067A
And the current through the resistor is:
[tex] \frac{100}{200} \cdot 0.067 = 33,5mA[/tex]
Do the same with the other source
[PLAIN]http://img69.imageshack.us/img69/9727/circuit12.png
I = 5/150 ~0.033A
[tex] \frac{100}{200} \cdot 0.033 = 16,5mA[/tex]
So the current I should be 50mA
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