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## Homework Statement

Use superposition to find V

_{0}in the circuit:

http://imageshack.us/a/img62/5567/eecircfinal1.jpg [Broken]

## Homework Equations

V = IR

Voltage division for 2 series resistors:

V across a resistor = (Resistor / total series resistance)(V in)

Current division for 2 parallel resistors:

Current through a resistor = (other resistor / math. sum of parallel resistors)(I in)

Superposition methods:

I = I' + I''

I' = current with circuit having voltage source shorted

I'' = current with circuit having current source cut out

## The Attempt at a Solution

Following the above & So for I' and the voltage source shorted:

http://imageshack.us/a/img29/8991/eecircfinal1edit1.jpg [Broken]

Then with current division,

I' = (4Ω/12Ω)(6A)

I' = 2A

Following the above again for I'' and with the current source cut out:

http://imageshack.us/a/img541/5840/eecircfinal1edit2.jpg [Broken]

And then since the resistors above are all in series then I just add to get R tot = 12Ω.

But then I = V/R

So then I'' = 24V / 12Ω

I'' = 2A,

BUT compared with the set superposition current direction in the diagram would it then be -2A?

If so, then the current I = I' + I'' would be 0 and then I think that would be wrong. I know afterwards after you get I from I' + I'', then V

_{0}is just V

_{0}= I*2Ω

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