Use superposition to find V0 in the circuit:
V = IR
Voltage division for 2 series resistors:
V across a resistor = (Resistor / total series resistance)(V in)
Current division for 2 parallel resistors:
Current through a resistor = (other resistor / math. sum of parallel resistors)(I in)
I = I' + I''
I' = current with circuit having voltage source shorted
I'' = current with circuit having current source cut out
The Attempt at a Solution
Following the above & So for I' and the voltage source shorted:
Then with current division,
I' = (4Ω/12Ω)(6A)
I' = 2A
Following the above again for I'' and with the current source cut out:
And then since the resistors above are all in series then I just add to get R tot = 12Ω.
But then I = V/R
So then I'' = 24V / 12Ω
I'' = 2A,
BUT compared with the set superposition current direction in the diagram would it then be -2A?
If so, then the current I = I' + I'' would be 0 and then I think that would be wrong. I know afterwards after you get I from I' + I'', then V0 is just V0 = I*2Ω
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