1. The problem statement, all variables and given/known data http://imageshack.us/a/img14/2387/homeworktest2prob2.jpg [Broken] a. Find the Thevenin equivalent circuit with respect to terminals a, B for the circuit. b. Find also the Norton equivalent circuit with respect to the terminals A, B, for the circuit 2. Relevant equations V = IR current division, voltage division, KCL, KVL Thevenin procedure, Norton procedure. 3. The attempt at a solution With the load cut out, 4Ω disappears and 25V/5Ω + 3A = Vb/20Ω 100V + 60V = Vb Vb = 160V, VTh = 160V I need help mainly with getting RTh I don't know if I can just simplify the resistors from A to B with that current source (do I cut it out so it becomes an open circuit? I know you put a wire to short the 25V while doing it though). Trying RTh = VTh/Ino instead, then a wire goes from a to b, then once I do that I try to use superposition (so might need help here with that to With the 3A cut out the equivalent R is 8.3Ω with 25V so I' = 3A then with the 25V silenced the current is just I'' = 3A, right? Because that's the total current in? So 3A + 3A = 6A Ino = 6A So for RTh I get 160V / 26.6A = 6Ω But I don't think it's correct.