- #1
KAaron
- 6
- 0
<Moderator's note: Moved from a technical forum and thus no template.>
Hi, I am a junior in high school and future physicist. I have a problem (I am very curious) and would like for it to be solved as I CAN NOT figure this out!
I was thinking about an object being dropped from rest from my aprox. height (2m) and its acceleration.
Using the formula in the title:
Vf^2=0^2+2*9.8*2=39.2
Sqrt(39.2)=6.26
Vf ~= 6.26m/s
Now I thought about the same object dropped from half the height. You would think, or at least I did, mathmatically you would do 6.26/2 which would be 3.13.
However, if you use the same formula the answer isn't the same.
Vf^2 = 0^2+2*9.8*1=19.6
Sqrt(19.6)=4.42
Vf ~= 4.42m/s
Why does it do this?
Hi, I am a junior in high school and future physicist. I have a problem (I am very curious) and would like for it to be solved as I CAN NOT figure this out!
I was thinking about an object being dropped from rest from my aprox. height (2m) and its acceleration.
Using the formula in the title:
Vf^2=0^2+2*9.8*2=39.2
Sqrt(39.2)=6.26
Vf ~= 6.26m/s
Now I thought about the same object dropped from half the height. You would think, or at least I did, mathmatically you would do 6.26/2 which would be 3.13.
However, if you use the same formula the answer isn't the same.
Vf^2 = 0^2+2*9.8*1=19.6
Sqrt(19.6)=4.42
Vf ~= 4.42m/s
Why does it do this?