- #1

KAaron

- 6

- 0

Hi, I am a junior in high school and future physicist. I have a problem (I am very curious) and would like for it to be solved as I CAN NOT figure this out!

I was thinking about an object being dropped from rest from my aprox. height (2m) and its acceleration.

Using the formula in the title:

Vf^2=0^2+2*9.8*2=39.2

Sqrt(39.2)=6.26

Vf ~= 6.26m/s

Now I thought about the same object dropped from half the height. You would think, or at least I did, mathmatically you would do 6.26/2 which would be 3.13.

However, if you use the same formula the answer isn't the same.

Vf^2 = 0^2+2*9.8*1=19.6

Sqrt(19.6)=4.42

Vf ~= 4.42m/s

Why does it do this?