Vibration Problem: Determine Period

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SUMMARY

The discussion focuses on determining the period of vibration for a uniform rod with a mass of 6 kg attached to a spring with a constant of 820 N/m. The rod is depressed by 10 mm and released, prompting the need to analyze the forces acting on the system. Key calculations include the spring force (8.2 N) and the weight of the rod (58.86 N). The solution involves using energy methods and conservation of energy to derive the equation of motion, from which the natural frequency and period can be calculated.

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Homework Statement


The uniform rod shown has mass 6 kg and is attached to a spring of constant k = 820 N/m. End B of the rod is depressed 10 mm and released.

Determine the period of vibration.

Picture is attached below

Homework Equations


Fs = kx
W = mg

The Attempt at a Solution


I honestly don't quite know how to even start a problem like this.
Fs = (820 N/m)(0.010 m) = 8.2 N
W = (6 kg)(9.81 N/kg) = 58.86 N
The spring force will act on the right end of the bar and the weight will act in the middle (@400 mm).

How am I supposed to proceed on this type of question? Do I need the torque about C?
 

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You may assume the situation shown is the equilibrium position.
Clearly there is a restoring force trying to go back to equilibrium and there is some inertia in going there.
The restraint at point C makes that indeed you need to consider torque and moment of inertia, so you are on the right track. Proceed !
 
The easiest approach is to use energy methods, based on kinetic and potential energies.
 
Dr.D said:
The easiest approach is to use energy methods, based on kinetic and potential energies.
How would that be done?
Initially the energy in the system would be the spring energy and perhaps relative gravitational energy. However, how would that be related to period?
 
Use conservation of energy to determine the equation of motion. The natural frequency falls out of the equation of motion, and the period is calculated from the natural frequency.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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