I Vibrations of waves with pinned vs free boundary conditions

AI Thread Summary
The discussion centers on the differences in wave frequencies associated with pinned versus free boundary conditions, particularly in musical instruments. Pinned boundaries result in higher frequencies due to shorter wavelengths, while unpinned boundaries create antinodes and longer wavelengths. The complexities of achieving these conditions in practical applications, such as with vibrating strings and diaphragms, are also noted. Various musical instruments, like flutes and oboes, demonstrate different resonant behaviors based on their boundary conditions and bore shapes. The conversation highlights the intricate relationship between boundary conditions and sound quality in musical acoustics.
member 428835
Hi PF!

Can someone explain to me why in math/physics the frequencies associated with waves (or say drum heads) tend to be larger when the boundaries are pinned as opposed to free? If possible, do you know any published literature on this?

Thanks!
 
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Consider a resonant column of air (like a flute). If you have an unpinned boundary it turns into an antinode and a pinned boundary turns into a node when you are thinking of the fundamental frequency. So with two pinned boundaries you have a wavelength equal to twice your tube length and with only one pinned boundary you have a wavelength equal to four times your tube length. The shorter wavelength corresponds to a higher frequency.
 
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I don't think this is all consistent. An unpinned boundary at each end will have a half wave resonance - same as with a pinned boundary at each end. There are practical difficulties achieving this, though. Open ends make it difficult to mount things like vibrating strings and diaphragms.
 
I was thinking pinned at one end and then the other end either pinned or unpinned. With most musical instruments it is hard to make both ends unpinned.
 
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Thank you both! Dale, is this in the literature anywhere formally?
 
Dale said:
I was thinking pinned at one end and then the other end either pinned or unpinned. With most musical instruments it is hard to make both ends unpinned.

Blowing on (across) the end of an open tube would qualify as that which (I suddenly remembered) applies to a flute and others. So actually all combinations are possible with common musical instruments.

I do remember that the lowest rank of organ pipes are closed end, which gives them an octave of range below the rest, for a given length. Quantity rather than sound quality perhaps.

That link again: But nothing is simple because (and again I heard this years ago and had forgotten) an oboe has a double reed and a nominally closed end, yet it has the same range as a flute, which is definitely open ended. The link seems to fudge that issue a bit but I guess it has to do with the difference between the balanced and unbalanced excitation of double and single reeds. Actually it cannot be simple (as if!) because a clarinet has a much more bass sounding note than an oboe, which is not what the basic statement about musical range would suggest. Oboe is very 'harmonicky', compared with the deep reedyness of a clarinet - but that's a whole new layer of complexity.
 
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@sophiecentaur well, your symphonic knowledge certainly exceeds mine! :bow:
 
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sophiecentaur said:
Actually it cannot be simple (as if!) because a clarinet has a much more bass sounding note than an oboe, which is not what the basic statement about musical range would suggest. Oboe is very 'harmonicky', compared with the deep reedyness of a clarinet
I believe the bore of a clarinet is cylindrical whereas the oboe is conical; this is also true for the trumpet and the flugelhorn. In each case the length is the same.
 
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Dale said:
@sophiecentaur well, your symphonic knowledge certainly exceeds mine! :bow:
I got to Grade 2 on Violin. The rest of my life has been played by ear!
 
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This is sort of fun. Apparently each horn is more "conical" trumpet<cornet< flugelhorn< mellophone. Live and learn:

 
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