Virial Theorem for an expanding globular cluster

AI Thread Summary
The discussion centers on applying the virial theorem to an expanding globular cluster, particularly in calculating kinetic energy and gravitational potential energy. The user expresses uncertainty in interpreting the problem and seeks clarification on how to utilize the theorem effectively. They have derived equations for mean square speed and potential energy but are unsure about the correct approach. Additionally, the conversation touches on determining the gas fraction at which the cluster becomes disrupted due to gas expulsion from stellar winds and supernovae. The user requests assistance in resolving these complex calculations.
Barbequeman
Messages
7
Reaction score
1
Homework Statement
You may make the assumption that the gas and stars are distributed as sphere of constant density and some finite radius rc. The total mass of the stars and of gas is different: assume that the total mass of the gas, Mg, is given by Mg = f M*, where M* is the total mass of the stars.

Start by assuming that the system overall is unrotating and in equilibrium. Calculate the kinetic energy of the stars in terms of rc, f, and M*. Therefore also calculate the total energy of the system.
Relevant Equations
2K+U=0 the basic equation for the virial theorem in a system which is unrotating and in equilibrium
I attached a file which shows my attempt to resolve this problem with the possible two pair interaction which gives us the kinetic energy of the cluster in an expanding system, at least I think so. But to be honest I´m more or less completely stuck with this question and I would be glad if somebody could explain me how to use the virial theorem in this special case.
 

Attachments

  • TEST.jpg
    TEST.jpg
    40.1 KB · Views: 119
Physics news on Phys.org
The overall reasoning looks good but I'm unsure how the question is supposed to be interpreted. The total (gas + star) mass is ##(1+f)M^*## and it looks as if they'd like us to distribute that uniformly over a sphere of radius ##r_c##. That would have a gravitational potential energy of\begin{align*}
\Omega = \dfrac{-3G(1+f)^2 {M^*}^2}{5r_c}
\end{align*}Then, assuming the gas to have negligible kinetic energy would imply that the mean square speed ##\langle v^2 \rangle## of the stars is\begin{align*}
\langle v^2 \rangle = \dfrac{2T}{M^*} = \dfrac{-\Omega}{M^*} = \dfrac{3G(1+f)^2 M^*}{5r_c}
\end{align*}I don't know which way is right...
 
  • Like
Likes PhDeezNutz and Barbequeman
I think I resolved it with the help of my friend from the university to crack the kinetic energy question which is the
 

Attachments

  • Virial_Theorem_Mark.jpg
    Virial_Theorem_Mark.jpg
    20.2 KB · Views: 113
The next question would be how to resolve towards f, at what gas fraction f the cluster is disrupted

The question in according to our Book is
Now suppose that winds from young stars and supernovae explosions very rapidly (you can assume instantaneously) expel the gas from the system. At what gas fraction f is the cluster disrupted?

With best wishes and thank you for your help
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top