TSny said:
You can make your equations more readable if you use some of the tools available on the toolbar at the top of the posting window. For example:
Here is my attempt at reformating your equations:
(1) dW = W1 cos30 dx cos0 + WB cos45 dx cos180 = 0
(2) dW = W1 sin30 dh1 cos0 + WA dhA cos180 + WB dhB cos180 = 0
Please correct these if they do not represent what you intended.
Thank you for the tip, I'll use these tools from now on.
Yes, the equations are exactly what I wanted to write.
TSny said:
Also, you should always define the symbols that you use. In particular, what do the quantities dx, dh1, dhA, and dhB represent?
I had it on my paper (not posted) but I understand it would be clearer if I wrote what they were. So, dx represents a small displacement to the left, dh1 a small displacement downwards from W1, dhA a small displacement upwards from WA, and dhB a small displacement upwards from WB. I'll attach a picture so you can see my thought process better and point out any mistakes.
All of these occur as a consequence of the small imaginary movement on W1.
TSny said:
Your second equation looks odd to me. Consider the first term on the right side. If dh1 is how far the 1 kg mass moves downward, then shouldn't the work done by gravity on this mass be W1⋅dh1⋅cos0 instead of W1⋅sin30⋅dh1⋅cos0? Why do you have a factor of sin30?
Hmm, the idea was similar to the problem 2.5 from the same book, Feynman Exercises.
As you can see, I had to decompose the tension into Wsin45 so I could take a small displacement dy. In this case, dy represents a y displacement from the left edge of the plank upwards.
But now that you pointed it out I can see, or at least think, of what could be the main differences. In the main question, we are considering dh1 as the displacement from W1 downwards and so the factor sin30 and sin45 should be written in WA because there is where the tensions occur. So, WA= W1sin30 + WBsin45. While in 2.5 (Fig 2.3) the tension occurs at the left edge and also the important displacement is in the edge and dh, the imaginary displacement of W, is not necessary.Then the equation should become
(2) dW = W1 dh1 cos0 + WA dhA cos180 + WB dhB cos180 = 0
where WA = W1sin30 + WBsin45
I just saw that in the first (2) that I wrote, I didn't write WBsin45, following my wrong reasoning. I'd assume it was due to some conflict I was having between using the flawed equation or using the last version.
TSny said:
Feynman introduces the principle of virtual work in chapter 4 of volume 1 of the lectures. This is well before he discusses Newton's laws of motion in chapter 9. So this problem is probably meant to go with chapter 4. The principle of virtual work will yield the answer without having to use the idea of "net force equals zero for static equilibrium".
Indeed, I should use the principle of virtual work throughout this chapter. The main problem I have is from equation (1):
(1) dW = W1 cos30 dx cos0 + WB cos45 dx cos180 = 0
Cancelling dx and solving the cos we get
WB = √(3/2)
But from Newton's Laws:
W1cos30 = WBcos45
which is basically a reduced version of (1). So my question would be, am I applying virtual work on the worked solution provided above or am I going back to Newton's Laws?
TSny said:
You need to be clear on what you are taking to be your virtual displacement(s) for the principle of virtual work. You have two unknowns (WA and WB). You will need two independent equations. You can get these by imagining two independent virtual displacements of the system. There are several possibilities. For example, if you want to use the principle of virtual work to get your equation (1), consider a virtual, horizontal displacement dx of the knot where the three strings meet.
What do you mean by "two independent virtual displacements"? Is it what I've drawn in my picture? If not, could you please provide a picture so I can understand it better.
TSny said:
For a particular virtual displacement of the system, the three displacements dh1, dhA, and dhB can be related by geometry and trig.
Aha, I'll give it another try as I tried to relate them yesterday but I got a nonsensical answer. I'll come back to this post later. Could you correct any mistakes I made with my reasoning and if I am missing any important concept/idea as I have a hard time visualizing and solving problems with virtual work.