Voltage across a bulb affects power output

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Changing the voltage across a bulb directly affects its power output, with the relationship defined by the equation P=V×I. As voltage increases, power output increases, particularly when resistance remains constant, leading to the conclusion that power is proportional to the square of the voltage (P=V²/R). This means that higher voltage results in significantly greater power output due to the increase in current. It's important to note that resistance may not always be constant, as it can vary with temperature. Understanding these relationships is crucial for GCSE exam preparation.
gracep
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Homework Statement


I'm studying for my GCSE exam and I need to know how changing the voltage across a bulb affect it's power output for my secondary evidence, i have searched the internet for the answer but can't find anything. Anyone know how it affects it OR any useful websites to use? thankyou.

Homework Equations


P=VxI

The Attempt at a Solution


I have wrote that the bigger the voltage going into the bulb, the more the power output will be because P=VxI but I need to write more? thankyou.
 
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Hi gracep. You can write 3 "different" recipes for the power output:

P=V\cdot I
P=I^2\cdot R
P=V^2/R

These 3 things are all related through Ohm's Law.

What you need is something that relates voltage and power and where everything else in the equation is a constant.

So, it depends on the problem you have. If you have a constant intensity you would use the first relation. If you have a constant resistance (wich is probably the more common situation), then you want to use the third relation.

From that you can easily see how the power behaves when changing voltage.
 
What he said..

Rather than mentioning P=IV, I would point out that the power is proportional to V2.

That's because increasing V also increases I. It would be so better to rearrange the equation given using Ohms Law...

Ohms Law..
V=IR
so
I=V/R

You were given P=IV so substitute for I giving

P=V2/R

Hence power is proportional to V2.

I supose you might get an extra mark for pointing out that R might not be constant. It might vary with temperature.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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