Why does having a high input impedance and low output impeda

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alexdr5398
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Homework Statement


Say you connect Circuit A with low output impedance to circuit B with high input impedance. Why does this cause minimal voltage drop compared to connecting them the other way around (high output to low input).

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?
 
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alexdr5398 said:

Homework Statement


Say you connect Circuit A with low output impedance to circuit B with high input impedance. Why does this cause minimal voltage drop compared to connecting them the other way around (high output to low input).

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?
Think about Vin and Vout. When the output resistance of a stage is high into a low-input impedance stage, what happens to the Vin seen by the 2nd stage? Think voltage dividers... :smile:
 
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berkeman said:
Think about Vin and Vout. When the output resistance of a stage is high into a low-input impedance stage, what happens to the Vin seen by the 2nd stage? Think voltage dividers... :smile:

I've never learned about voltage dividers. Would the Vin in the 2nd stage be larger than the Vout in the 1st stage?
 
alexdr5398 said:

Homework Equations


P = V^2/R
P = IV

The Attempt at a Solution


I am guessing that the power must stay the same when going from circuit A to circuit B, so when the resistance increases, the voltage drops to keep the power equal. But why does this cause a "minimal" voltage drop. Wouldn't matching the impedance be the best way reduce the voltage drop?

I think you are confusing maximum power transfer and minimum signal (voltage) loss.
 
alexdr5398 said:
I've never learned about voltage dividers. Would the Vin in the 2nd stage be larger than the Vout in the 1st stage?
No, Google voltage divder circuits and do a little readng. You'll find that the Voltage Divider equaton is like this:

[tex]V_{out} = V_{in} \frac{R_d}{R_i + R_d}[/tex]

Try that search, and try answering again. :smile: