Voltage across a bulb affects power output

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SUMMARY

Changing the voltage across a bulb directly affects its power output, as defined by the equations P=V×I, P=I²×R, and P=V²/R. When voltage increases, power output increases proportionally to the square of the voltage, particularly when resistance remains constant. This relationship is derived from Ohm's Law, where voltage (V) is equal to current (I) multiplied by resistance (R). It is essential to note that resistance may vary with temperature, which can influence power calculations.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with electrical power equations
  • Knowledge of the relationship between voltage, current, and resistance
  • Basic concepts of electrical circuits
NEXT STEPS
  • Study the implications of varying resistance on power output
  • Explore the effects of temperature on resistance in electrical components
  • Learn about practical applications of P=V²/R in circuit design
  • Investigate the relationship between voltage and current in different types of bulbs
USEFUL FOR

Students preparing for GCSE physics exams, educators teaching electrical concepts, and anyone interested in understanding the principles of electrical power and circuit behavior.

gracep
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Homework Statement


I'm studying for my GCSE exam and I need to know how changing the voltage across a bulb affect it's power output for my secondary evidence, i have searched the internet for the answer but can't find anything. Anyone know how it affects it OR any useful websites to use? thankyou.

Homework Equations


P=VxI

The Attempt at a Solution


I have wrote that the bigger the voltage going into the bulb, the more the power output will be because P=VxI but I need to write more? thankyou.
 
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Hi gracep. You can write 3 "different" recipes for the power output:

[itex]P=V\cdot I[/itex]
[itex]P=I^2\cdot R[/itex]
[itex]P=V^2/R[/itex]

These 3 things are all related through Ohm's Law.

What you need is something that relates voltage and power and where everything else in the equation is a constant.

So, it depends on the problem you have. If you have a constant intensity you would use the first relation. If you have a constant resistance (wich is probably the more common situation), then you want to use the third relation.

From that you can easily see how the power behaves when changing voltage.
 
What he said..

Rather than mentioning P=IV, I would point out that the power is proportional to V2.

That's because increasing V also increases I. It would be so better to rearrange the equation given using Ohms Law...

Ohms Law..
V=IR
so
I=V/R

You were given P=IV so substitute for I giving

P=V2/R

Hence power is proportional to V2.

I supose you might get an extra mark for pointing out that R might not be constant. It might vary with temperature.
 

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