How Do You Calculate Voltage Across Each Resistor in a Mixed Circuit?

  • Thread starter Thread starter the_d
  • Start date Start date
  • Tags Tags
    Resistor Voltage
Click For Summary
SUMMARY

This discussion focuses on calculating voltage across resistors in a mixed circuit, specifically using Ohm's Law. Participants emphasize the importance of understanding series and parallel resistor configurations, as well as the correct application of formulas such as V = I * R. A key example illustrates how to find the voltage drop across a resistor when given total resistance and current, demonstrating that with a 12V source and a total resistance of 5430 ohms, the voltage across a 337-ohm resistor is 0.744 volts.

PREREQUISITES
  • Understanding of Ohm's Law (V = I * R)
  • Knowledge of series and parallel resistor configurations
  • Ability to calculate equivalent resistance in circuits
  • Familiarity with voltage drop calculations
NEXT STEPS
  • Learn how to calculate equivalent resistance in parallel circuits
  • Study the application of Kirchhoff's Voltage Law in circuit analysis
  • Explore practical examples of voltage division in series circuits
  • Investigate the impact of varying resistor values on circuit performance
USEFUL FOR

Electronics students, hobbyists, and engineers looking to deepen their understanding of circuit analysis and voltage calculations across resistors.

the_d
Messages
127
Reaction score
0
I have a 12V power source in a circuit and 4 resistors in a line and 1 on the side how do i find the voltage across each resistor?:confused:
 
Engineering news on Phys.org
You haven't given us resistor values and your description is vague. Oh yeah by the way, this sounds like homework.
 
Do you have a diagram?

From your description it seems like all of the resistors are in series. Do you know what to do when resistors are in series?

After you find that out, use Ohm's Law.
 
Try to simply the circuit by combining the resistors to get an equivalent circuit. If ur resistors is in series, add the resistance. If in parallel do 1/r+1/r2=1/Requvilant.
 
Well, asking the current (I) with no resistance is like asking how long is a piece of string to find the total Resistance in a parralel circuit then =
R1 X R2 / R1 + R2

And the current can be worked out by I = V/R
 
I have a 12V power source in a circuit and 1 resistors in a line of 1k , how do i find the voltage across resistor?

please help me?

i want some basic formula so i can calculate the voltage across each resistor..

thank you
 
If you have 12 volts across a string of resistors in series. the current flowing is 12 / total resistance.
Say the total resistance is 5430 ohms. The current will be 12 volts / 5430 ohms = 2.21 mA

Now, this current flows through all the resistors in series, so the voltage across anyone of them = I * R.

If R= 337 ohms, then the voltage across it will be 0.00221 amps * 337 ohms = 0.744 volts.You can get the same result by doing it like this: 12 volts * 337 ohms / 5430 ohms = 0.744 volts.

So, if you know the total resistance and the voltage across it, you can work out the voltage across any resistor in the series string.
 
Hello,

Thanks for reply. i have read somewhere that to find out the voltage across resistor do this

Calculate the amount of voltage drop or reduction in an electrical circuit that has a power source of "100" volts at "0.1" amperes and a resistor of "100" ohms. Using the formula "V=I*R" the equation would result "V= 0.1*100". The answer would be "10" volts. This means that a voltage reduction of "10" volts would occur across the "100"-ohm resistor and the circuit would have only "90" volts of power past the resistor placed in the circuit.

is that right ?

but when i do myself i am not getting correct values.

i have 0.02 mA and 1kohms but when i multiple that i write this way :

0.02 * 1000 = 20v

this is not right i have 12v main power and after doing this i am getting 20v how it will subtract 20 from 12.

then i found 1 more simple formule to figure it out what resistor i need for any object,

e.g.

r = es - eb / i

12v - 5v / 0.02 = 350 ohms

is this also right ?

please help me...
 
The Ohms Law calculations have to be done with Volts, Amps and Ohms.

So, if you have 0.02 mA you need to convert this to 0.00002 Amps before doing the calculation.

So this one:
12v - 5v / 0.02 = 350 ohms
should be
7 / 0.00002 = 350 K
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
80
Views
5K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
3
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
68
Views
7K
  • · Replies 33 ·
2
Replies
33
Views
3K
Replies
3
Views
2K
Replies
7
Views
2K