Calculating Voltage Across a Capacitor

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SUMMARY

The discussion centers on calculating the voltage across a capacitor in a circuit with a time constant of τ=RC=7s. The initial current is correctly calculated as 0.2A using the formula v/Req=300/1489. However, the voltage calculated using V=IR yields 145.73V, which is incorrect as the expected result is 153V. The confusion arises from the application of the voltage formula V=IR, which does not directly apply to the voltage across a capacitor during charging.

PREREQUISITES
  • Understanding of capacitor charging equations, specifically I(t)=I_0 e^{-t/\tau}
  • Knowledge of time constant calculation using τ=RC
  • Familiarity with Ohm's Law, V=IR
  • Basic circuit analysis skills
NEXT STEPS
  • Study the relationship between current and voltage in capacitors during charging
  • Learn about the concept of voltage across a capacitor over time
  • Explore the effects of different resistor-capacitor (RC) combinations on charging behavior
  • Review the derivation of the voltage across a capacitor as a function of time
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone working on circuit analysis involving capacitors.

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Homework Statement



[PLAIN]http://img189.imageshack.us/img189/4555/capacitorh.jpg


Homework Equations



I(t)=I_0 e^{-t/\tau} (current as a function of time for a capacitor being charged)


The Attempt at a Solution



The time constant of the circuit is τ=RC=7s. And the initial current in the circuit is

v/Req=300/1489=0.2A (I know this is correct)

Now pluging into the equation:

I(5)=0.2 e^{-5/7}=0.0979 \ A

V=IR= 0.0979 \ A \times 1489 \Omega = 145.73 \ V

But the correct solution must be 153V. I'm very confused, what's wrong with my working? :confused:
 
Last edited by a moderator:
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Is V=IR the voltage across a capacitor? ehild
 

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