Voltage drop across paralell resistor and capacitor

Click For Summary
SUMMARY

The discussion focuses on calculating the voltage drop across a resistor and capacitor in parallel using complex impedance. The parameters provided include a current of 100 milli Amps, a resistance of 1000 ohms, and a capacitance of 0.001 Farads at a frequency of 60 Hz (377 rad/s). The correct approach involves calculating the complex impedance of the capacitor using the formula Z_c = 1/(i*omega*C) and then applying the parallel resistor formula R_eq = (R*Z_C)/(R+Z_C). The magnitude of the resulting complex voltage can be determined by taking the square root of the product of the complex quantity and its conjugate.

PREREQUISITES
  • Complex impedance calculations
  • Ohm's law application in AC circuits
  • Understanding of parallel resistor and capacitor configurations
  • Basic knowledge of complex numbers and their magnitudes
NEXT STEPS
  • Study complex impedance in AC circuits
  • Learn how to apply Ohm's law to complex quantities
  • Explore the calculation of voltage drops in parallel circuits
  • Investigate the use of complex conjugates in electrical engineering
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits with resistors and capacitors.

teroenza
Messages
190
Reaction score
5

Homework Statement


Find the voltage drop across a resistor and capacitor in parallel. I am trying to understand how to deal with this using complex numbers. I may have a completely wrong notion of complex impedance. I thought I could treat the complex impedance like resistance, then take the modulus or real part (I believe I know the math, but not which to apply).


I= 100 milli Amps
R= 1000 ohms
C= 0.001Farads
freq.= 60Hz=377rad/s



Homework Equations


Z_c=1/(i*omega*C)

R_eq= (R*Z_C)/(R+Z_C)


The Attempt at a Solution


Do I apply the standard resistors in parallel formula then take the real part of the modulus? Or do I have a completely wrong conception on complex impedance.
 
Physics news on Phys.org
teroenza said:

Homework Statement


Find the voltage drop across a resistor and capacitor in parallel. I am trying to understand how to deal with this using complex numbers. I may have a completely wrong notion of complex impedance. I thought I could treat the complex impedance like resistance, then take the modulus or real part (I believe I know the math, but not which to apply).


I= 100 milli Amps
R= 1000 ohms
C= 0.001Farads
freq.= 60Hz=377rad/s



Homework Equations


Z_c=1/(i*omega*C)

R_eq= (R*Z_C)/(R+Z_C)


The Attempt at a Solution


Do I apply the standard resistors in parallel formula then take the real part of the modulus? Or do I have a completely wrong conception on complex impedance.

Calculate the complex impedance as you've suggested using the 'usual' formula for resistors in parallel. Apply Ohm's law to find the (complex) voltage that will appear across the net impedance when driven by the 100mA current. The magnitude of that complex quantity should be what you're looking for.
 
To be sure I fully understand, by magnitude you mean take the square root of (my complex quantity * its complex conjugate) ?
 
teroenza said:
To be sure I fully understand, by magnitude you mean take the square root of (my complex quantity * its complex conjugate) ?

Yes.
 

Similar threads

Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
929
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
7K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K