Voltage drop over dependent current source?

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Homework Help Overview

The discussion revolves around a circuit analysis problem involving mesh currents and a dependent current source (CCCS) shared by two meshes. The original poster expresses concern about potential voltage drops across the dependent source and how this might affect their mesh current equations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of ignoring the dependent current source in mesh current calculations. Suggestions include converting the current source and a resistor to a Thevenin equivalent and introducing a new variable for the voltage drop across the current source.

Discussion Status

Some participants have provided guidance on possible approaches to incorporate the dependent source into the mesh equations. There is an ongoing exploration of methods, including the use of Thevenin and Norton equivalents, while maintaining the dependencies of the sources.

Contextual Notes

The original poster has not provided a circuit diagram, which may limit the clarity of the discussion. There is an emphasis on understanding how to handle dependent sources in mesh analysis without reaching a definitive conclusion.

Inertigratus
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I have a circuit with 3 meshes for which I have to find the mesh currents, and I have.
However, I just thought that there might be a voltage drop over the dependent current source in the circuit, which would change the mesh current equations.
The CCCS is shared by two meshes.
When I did the calculations I simply ignored the CCCS.
Any ideas?
 
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Inertigratus said:
I have a circuit with 3 meshes for which I have to find the mesh currents, and I have.
However, I just thought that there might be a voltage drop over the dependent current source in the circuit, which would change the mesh current equations.
The CCCS is shared by two meshes.
When I did the calculations I simply ignored the CCCS.
Any ideas?

Can you post the circuit diagram?
 
Sure, http://img692.imageshack.us/img692/7081/namnlskei.jpg
I'm not asking for the solution, just wondering what I should do with the dependent source when writing the mesh equations?
 
Last edited by a moderator:
Two suggestions. First, you could convert the current source and the 4R resistor in parallel with it to a Thevenin equivalent voltage source. That would let you write the KVL mesh equations without worrying about mystery voltages. It would also reduce the circuit to just two loops.

Second, you could introduce a new variable, say vx, which is the voltage drop across the current source, and one new equation (with a new variable you need another equation). This equation would be the additional constraint on the mesh currents implied by the current source, namely i2 - i3 = k*i1.

attachment.php?attachmentid=38884&stc=1&d=1316101327.gif


I think that the first suggestion would be simpler. Note that the third mesh current i3 is strictly dependent upon the voltage vx via Ohm's Law with the 4R resistor.
 

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I see, thanks!
So it's possible to use Thévenin and Norton equivalents when the sources are dependent as well?
 
Inertigratus said:
I see, thanks!
So it's possible to use Thévenin and Norton equivalents when the sources are dependent as well?

Sure, as long as you maintain the dependencies through the calculations.
 

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