Voltage Drops in Series Resistors

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Homework Help Overview

The discussion revolves around calculating the voltage drop between two points, P and Q, in a circuit with multiple resistors arranged in series and parallel configurations. Participants are exploring the application of Ohm's law and the principles of series and parallel resistors.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to start the problem and considers analyzing the circuit's potential changes. Other participants suggest clarifying the arrangement of resistors and offer guidance on visualizing the circuit layout. Questions arise regarding the calculation of voltage drops and the relationship between current and voltage across the resistors.

Discussion Status

Participants are actively engaging with the problem, with some offering suggestions for visualizing the circuit and clarifying the relationships between the components. There is a mix of interpretations regarding the calculations needed, and while some guidance has been provided, no consensus has been reached on the next steps.

Contextual Notes

There are indications of confusion regarding the arrangement of resistors and the voltage drops involved, as well as the need for clarity on how to approach the calculations without making assumptions about the circuit's behavior.

Drizzy
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Homework Statement


http://imgur.com/bCTKUIs

What is the voltage between P and Q?

Homework Equations

The Attempt at a Solution



Don't know how to begin. I thought maybe I could walk around the circuit to se how the potential changes. Is that a good idea?
 
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You should know Ohms law and how to add resistors in parallel and series configuration.
 
yes I know how to do that. How should a solve this problem?
 
Hi Drizzy:

I think the way the figure is drawn makes it tricky to see what resistances are in series and in parallel. I suggest a layout that shows one resistor with the 12 volts across it, and
the other three resistors as a series of two parts: one with one resistor, and the other with two resistors in parallel.

Good luck.

Regards,
Buzz
 
As you can see resistor 15_ohms and 20ohms share the same nodes, so they are parallel thus can replaced by equivalent resistor.
 
I know that the voltage across the to parallell resistors is 12 aswell. So the current going through it is 12/68,57..

then I can multiply it with 60/7

Is that right?
 
  • #10
Drizzy said:
I know that the voltage across the to parallell resistors is 12 aswell. So the current going through it is 12/68,57..

then I can multiply it with 60/7

Is that right?
No, there is also a voltage drop across the 60 Ω resistor.
 
  • #11
Hi Drizzy:

The diagram linked in your post #7 show two resistances in series. You want to get the voltage drop across one of them. You don't need to calculate any currents. The same current goes through both resistors. You already know the sum of the voltage drops across both resistors.

Hope that helps.

Regards,
Buzz
 

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