Voltage Regulators: Understanding Transistors Biasing at 11:35

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SUMMARY

The discussion centers on the understanding of voltage regulators, specifically the biasing of transistors. At 11:35 in the referenced video, the speaker explains that the equation Vb = Vcc/(R1 + R2) applies because the base current (IB) is negligible. This allows for the assumption that the current through resistors R1 and R2 is the same, effectively treating them as a series voltage divider. The key takeaway is that R1 and R2 are not in parallel, and the approximation of IB being small is valid in many practical scenarios.

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hi i can't understand something in voltage regulators

http://www.youtube.com/watch?v=9FJJre-HG_0&feature=channel

at 11:35 he starts explaning why Vb's equation is like that but i don't get it

at 12:00

he says that Vcc/(R1+R2) gives the current through the two resistors

but how is that possible? I mean in the circuit these two resistors don't have the same current because they are connected in parallel, so why does he say that they have the same current?

i can't get it, i would appreciate any explanation, this is the only thing that i can't understand from his lecture and i really need to understand it because i can't solve problems because of it

thanks in advance
 
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R1 and R2 aren't connected in parallel. Why do you think they are?

He's using the approximation that the base current IB is very small, so you can neglect it. This means all the current flowing through R1 also goes through R2. In other words, R1 and R2 are effectively in series so you have a simple voltage divider.
 
vela said:
R1 and R2 aren't connected in parallel. Why do you think they are?

He's using the approximation that the base current IB is very small, so you can neglect it. This means all the current flowing through R1 also goes through R2. In other words, R1 and R2 are effectively in series so you have a simple voltage divider.

thanks a lot ;)

one more question, can we always assume that Ib is too small?
 

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