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Volume and surface area of a cylinder

  1. Sep 7, 2009 #1
    1. The problem statement, all variables and given/known data
    I need the ratio like in the image below
    http://img228.imageshack.us/img228/4015/foiessa.jpg [Broken]
    I guess as a function of D.

    2. Relevant equations
    Volume of a cylinder: pi*r^2*h
    Area: 2*pi*r*(h+r)


    3. The attempt at a solution

    No clue.
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Sep 7, 2009 #2

    Integral

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    You have expressions for the area and volume, you are told to compute the ratio

    [tex] \frac {Volume} {Area} [/tex]

    What is your problem?
     
  4. Sep 8, 2009 #3
    The area of a cylinder, as far as I remember, is: 2*pi*r*h +(2*pi*r^2)
     
  5. Sep 8, 2009 #4
    Now find the the volume, and divide that by area.

    V= d^2*pi*h

    A= (2*pi*d*h) + (2pi*d^2)

    And now write V/A = (d^2*pi*h)/[(2*pi*d*h) + (2pi*d^2)]

    I hope I am right, and that it helps! :)
     
  6. Sep 8, 2009 #5

    Integral

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    That is a good start. Now do some simplification.
     
  7. Sep 8, 2009 #6
    d isn't the radius though.
     
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