Volume by Rotating a Curve: Finding the Solid Between Two Curves

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Homework Help Overview

The problem involves finding the volume of a solid obtained by rotating the region bounded by the curves x=1+(y-2)^2 and x=2 about the x-axis, specifically using the method of cylindrical shells.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of cylindrical shells and question the correctness of the formula and limits used for integration. There is an attempt to verify the intersection points of the curves and the corresponding y-values.

Discussion Status

Some guidance has been offered regarding the formula for the volume of a cylindrical shell, and there is an ongoing exploration of the correct limits of integration based on the intersection points of the curves.

Contextual Notes

Participants are checking the accuracy of their integration limits and the formula used, indicating uncertainty about the setup of the problem.

mikhailpavel
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Homework Statement


Hey i have a problem here with volume by cylindrical shells. i wanted to find the given volume of the solid obtained by rotating the region bounded by the curves x=1+(y-2)^2 and x=2 about the x axis.


Homework Equations


we tried to integrating 2 phi f(y) dy with upper limit 3 and lower limit 1.


The Attempt at a Solution


we got the answer 33.5 but i don't think it is the correct one.
immediate help will be appreciable.
 
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You are using cylindrical shells, but your formula is incorrect. A typical shell in this problem has a volume of 2pi*y*(x2 - x1)*dy

x2 is the x-value on the line x = 2, and x1 is the x-value on the parabola. You have graphed the region being revolved, right?
 
can u tell me if my upper and lower limits are right because still i am not getting the right answer..i think!
 
Yes, the two curves intersect at (2, 1) and (2, 3) so y ranges between 1 and 3.
 

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